Tony Pulls Wagon: Work Problem Solutions

[rhxoehwhfh]

Tony pulls his wagon a distance of 15 m across the garden while applying a force of 160 N on the wagon’s handle. If the handle makes an angle of 40degree with the horizontal, how much work did Tony do on the wagon?

I have an idea that W= F*D but why does question have the fact that handle makes an angle horizantal 40 degree angle?...

 

[Astronuc]

Because one is looking for the work applied in the direction of travel (and parallel with the horizontal). The force at an angle has horizontal and vertical components. Only the force parallel to travel is doing the work. The normal force is static since the wagon is not gaining elevation in the gravity field.

 

[rhxoehwhfh]

so degrees doesn't affect the amount of work?...

 

[rhxoehwhfh]

does anyone know this problem??

 

[rock.freak667]

You have to resolve the force into vertical and horizontal components. the component that is in the same direction as the force you call that F_1 and then you use the formula W=F_1s where s is the displacement IN THE DIRECTION OF THE FORCE.

yes the angle at which the force acts varies that amount of work that it does

 

[Astronuc]

so degrees doesn't affect the amount of work?...

Resolve the force into vertical and horizontal components.

Using the angle \theta with respect to horizontal, F_H = F cos\theta, which is the force doing the work,

and vertical, F_V = F sin\theta

or x (horizontal) and y (vertical).

If one does F*d, where * implies the dot product of the force vector and the displacement vector, then the cos of the angle is part of the solution. The dot product means one is applying the component of force parallel with the direction of displacement.

 

[rhxoehwhfh]

thank you