Topology: Connectedness and continuous functions

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SUMMARY

The theorem discussed states that a topological space \(X\) is connected if and only if for any continuous function \(f: X \to D\) (where \(D\) is a discrete space), the function \(f\) is not onto. The proof is structured in two parts: the first part establishes that if \(X\) is connected, then any continuous function cannot be onto, while the second part shows that if all continuous functions are not onto, \(X\) must be connected. A suggestion for improvement includes clarifying the phrasing in the proof to specify "Conversely, suppose for all continuous functions" for better accuracy.

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perwiradua
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Could you please check the statement of the theorem and the proof? If the proof is more or less correct, can it be improved?

Theorem

Let
gif.gif
be a topological space and
gif.gif
be the discrete space.

The space
gif.gif
is connected if and only if for any continuous functions
gif.gif
, the function
gif.gif
is not onto.

Proof

Only if:

Suppose the space
gif.gif
is connected and suppose there exists a continuous function
gif.gif
which is onto. Then
gif.gif
since
gif.gif
is onto. Also since
gif.gif
is continuous,
gif.gif
is open and a proper subset of
gif.gif
. Let
gif.gif
and
gif.gif
. Both
gif.gif
and
gif.gif
are
proper and nonempty and clopen, and
gif.gif
. But this contradicts the connectedness of
gif.gif
.


If:

Conversely suppose for all functions
gif.gif
, the function
gif.gif
is not onto. Suppose
gif.gif
is disconnected, say
gif.gif
where
gif.gif
are clopen and
gif.gif
. But then the function

gif.gif


is continuous and onto.
 
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Looks good but for (ii) you should say "Conversely, suppose for all continuous functions"
 

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