Torque & Force Homework Solution

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The discussion revolves around solving a physics problem involving a wrecking ball supported by a boom and a tension cable. The key equations used include the sum of torques and forces in both the x and y directions to find the tension in the support cable and the force exerted by the hinge. The calculations led to a tension of 12,455 N in the support cable and a hinge force of 10,562 N in the x-direction, with a vertical force of 875 N. The original poster expresses uncertainty about their solution and seeks confirmation or assistance. The thread highlights the importance of applying equilibrium equations correctly to solve for unknown forces in static systems.
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Homework Statement



A wrecking ball (weight = 4800 N) is supported by a boom, which may be assumed to be uniform and has a weight of 3600 N. A support cable runs from the top of the boom to the tractor. The angle between the support cable and the horizontal is 32, and the angle between the boom and the horizontal is 48. Find (a) the tension in the support cable and (b) the magnitude of the force exerted on the lower end of the boom by hinge at point P.


Homework Equations


\SigmaT = Fr = 0
\SigmaFx = -Tcos\Theta + Rx = 0
\SigmaFy = -Wball - Wboom +Tsin\Theta+Ry = 0

The Attempt at a Solution


\SigmaT = 3600 (L/2) + 4800 L - Ft sin32 L = 0
\SigmaT = 1800 L + 4800 L = Ftsin32L
\SigmaT = 6600 = Ft sin 32
Ft = 12455N

Fx = -Ftcos32 + Rx = 0
Fx = -12455 cos 32= -Rx
Rx = 10562 N

Fy = -4800 - 3600sin48 + Ftsin 32 + Ry = 0
Fy = -4800 -3600sin48 + 12455sin 32 +Ry = 0
Ry = 875N
 
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My physics teacher gave us a set of bonus problems over break and I cannot figure this one out. I got an answer but I do not think it is right. If anyone knows how to do this, could you please help me out. Thank you very much
 

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