Torque on a rotating system system

AI Thread Summary
The total moment of inertia for the rotating system is calculated as 2ml²Sin²θ, leading to an angular momentum of 2ml²ωSin²θ. To find the torque, differentiating the angular momentum is necessary, but the absence of time-dependent terms poses a challenge. The discussion emphasizes the need for a vector expression of total angular momentum to assess changes in direction. It is recommended to use the vector definition of angular momentum for a point particle, with the origin positioned at the center of the rod. This approach will provide the necessary information to calculate the torque effectively.
Saptarshi Sarkar
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Homework Statement
A thin massless rod of length 2l has equal point masses m attached at its ends (see
figure). The rod is rotating about an axis passing through its centre and making angle θ with it. What is the magnitude of the rate of change of its angular momentum?
Relevant Equations
##L=Iω##
##τ=Iα=\frac {dL}{dt}##
IMG_20200206_001717.jpg


I calculated the total moment of inertia of the system to be ##2ml²Sin²θ##, so the angular momentum is ##2ml²ωSin²θ##.

To get the torque on the system I need to differentiate the angular momentum but I don't have any time dependent terms. What should I do?
 
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Your expression gives only the vertical component of angular momentum. You’re going to need the vector expression for the total angular momentum in order to see if the direction of angular momentum is changing.

So, use the vector definition of angular momentum for a point particle. Take the origin at the center of the rod.
 
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