Torque Problem, need to verify answer

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The problem involves calculating the net torque on a circular blade of a radial arm saw as it slows down from 262 rad/s to 85 rad/s over 18 seconds. The moment of inertia for a uniform solid disk is correctly identified as 1/2 * m * r^2. The angular deceleration is calculated as -10 rad/s². Using the formula for torque, the net torque is found to be approximately 0.0338 Nm. The calculations and assumptions regarding the moment of inertia and angular deceleration appear to be correct.
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Homework Statement


The circular blade on a radial arm saw is turning at 262 rad/s at the instant the motor is turned off. In 18.0 s the speed of the blade is reduced to 85 rad/s. Assume the blade to be a uniform solid disk of radius 0.130 m and mass 0.400 kg. Find the net torque applied to the blade.

Homework Equations


Sum torque=moment of inertia X angular deceleration

The Attempt at a Solution


ΣT=Ia
a=(Wf-Wi)/t=(85-262)/18=-10 rad/s
ΣT=.5mr^2*a
=.5*.4(.13)^2*10 = .0338 Nm
 
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I think the moment of inertia for a uniform solid disk is 1/2*m*r^2.
 
Anadyne said:
I think the moment of inertia for a uniform solid disk is 1/2*m*r^2.

my bad, changed.
 
I don't see anything else wrong... but I could be wrong. ^^;
 
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