Torque required to decelarate a disc

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To decelerate a disc mounted on a rotating shaft with a moment of inertia of 170 kgm² from 20 degrees/sec to a stop within 80 degrees of travel, the torque required can be calculated using the relationship T = Iα. The initial angular velocity (ωi) is 0.34 rad/sec, and the final angular velocity (ωf) is 0. The time to stop (Δt) cannot be assumed as 4 seconds without considering the deceleration curve, and it is suggested to treat it as a variable. The stopping distance can be determined by setting the initial and final angles in the equation, incorporating the inertia correctly into the calculations. The discussion emphasizes the importance of accurately applying the equations of motion to solve for torque and stopping distance.
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Hello everyone if someone can helo me out here
I have a rotating shaft wiht a disc mounted on it.The moment of inertia of the total system is 170 kgm2.It is rotating with a veolicty of 20 deg /sec.i want to bring it to stand still within 80 deg travel from the application of brakes

I=170 kgm2
wi=20 deg/sec=0.34 rad/sec
wf=0
Δt=4 sec(taken from the fact that it is moving at speed of 20 deg/sec,80 deg/sec will be covered in 4 sec.Please correct as i m not sure abt this value)

So
T=Iα
T=I(Δω/Δt)
T=(170) (0-0.34/4)
T= -14.45Nm

Please correct and help
 
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Shady99 said:
Δt=4 sec
You cannot simply set it as 4 seconds because when it slow down, the disc stop before it rotate 80 deg after the application of brakes.

Just leave it as variable and consider
T = \dfrac{d\omega}{dt} = \dfrac{d\theta}{dt} \dfrac{d\omega}{d\theta} = \omega \dfrac{d\omega}{d\theta}.
When you integrate it as \theta, then
\int_{\theta_i}^{\theta^f} T d\theta = T(\theta_f - \theta_i)
and also it is same as
\int_{\theta_i}^{\theta^f} T d\theta = \int_{\omega_i}^{\omega_f} \omega d\omega = \dfrac{1}{2} \left(\omega_f^2 - \omega_i^2\right).
 
hey thnks for the reply...can you elaborate it more...possibly solve it
 
Use the last relation,
T(\theta_f - \theta_i) = \dfrac{1}{2} (\omega_f^2-\omega_i^2),
for your situation. You already know each variable without T, so it is elementary calculation
 
ok thnks...but can't i determine a stopping distance?
 
Shady99 said:
ok thnks...but can't i determine a stopping distance?
You mention that you want to stop the disc within 80 deg,
Shady99 said:
I have a rotating shaft wiht a disc mounted on it.The moment of inertia of the total system is 170 kgm2.It is rotating with a veolicty of 20 deg /sec.i want to bring it to stand still within 80 deg travel from the application of brakes
so just set \theta_i = 80^\circ and \theta_f = 0. It's up to you.
 
And what abt the inertia...i see you have ignored inertia in your equations
 
Oh! Sorry. I used T for the angular acceleration. The equation should be
\alpha (\theta_f - \theta_i) = \dfrac{1}{2} (\omega_f^2-\omega_i^2),
and then
T = I \alpha.
It's my mistake.
 

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