Torque Required to Spin Solid Cylinder

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Discussion Overview

The discussion revolves around calculating the torque required to spin a solid cylinder with an attached flywheel, focusing on the effects of the flywheel's diameter on torque and rotational dynamics. Participants explore the relationship between force, torque, and the mechanics of rolling resistance.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant calculates the force required to overcome rolling resistance and derives the torque needed to maintain rotation, asserting that it requires 64.746 N of force and 8.222 Nm of torque.
  • Another participant suggests that increasing the flywheel's diameter increases torque due to the larger radius, while also implying that the speed of rotation decreases.
  • A third participant introduces the distinction between linear and rotational mechanics, suggesting that the confusion arises from applying linear equations to a rotational scenario.
  • One participant clarifies the difference between rolling resistance and the coefficient of friction, questioning whether the cylinder or the flywheel is rolling on the steel rollers, which affects the torque calculation.
  • Another participant agrees that applying force further from the center increases torque but questions the assumption that a larger diameter would require less torque, noting that a larger moment of inertia makes rotation harder.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between flywheel diameter, torque, and rotational dynamics. There is no consensus on the implications of increasing the flywheel's diameter or the correct interpretation of the torque calculations.

Contextual Notes

Participants highlight the need for clarity on whether the cylinder or the flywheel is rolling, which affects the calculations. The discussion also reflects uncertainties regarding the application of linear versus rotational mechanics and the implications of moment of inertia in torque calculations.

jafolkerts
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I am working on a project and I am having a bit of difficulties with the math. It has been awhile since I took physics in college so please bear with me.

I am attempting to calculate the amount of torque required to spin a solid cylinder resting upon a set of steel rollers. Attached to the cylinder is a flywheel that is 14" in diameter or 0.127 meters in radius.

Relevant Data
Cylinder plus flywheel mass = 2750 kg
Flywheel radius = 0.127 m
Cylinder rolling resistance upon steel rollers (Coefficient of friction (\mu)) = 0.0024

At this point, I am merely trying to calculate the amount of effort required to maintain a constant rotation.

Here is my working theory:

First, we need to calculate the force (F_c{}) that is required to overcome the rolling resistance of the cylinders on the steel rollers:

F_c{} = \muN
\mu = Coefficient of friction = 0.0024
N = Normal Force = MG (M = mass of cylinder (2750 kg) and G = Earth's gravitational acceleration (9.81 m/sec2))
N = (2750 kg)(9.81 m/sec2)
N = 26,977.5 N

F_c{} = (0.0024)(26,977.5 N)
F_c{} = 64.746 N

I assert that it will take at least 64.746 N of force to spin the cylinder. Assuming this is correct, I would now like to calculate the torque required to spin this cylinder by applying this force to the edge of the flywheel using this formula:

Torque = Force x Distance
Torque = (64.746 N)(0.127 m)
Torque = 8.222 Nm

Here's the issue that I am having troubles with: if I increase the flywheel's diameter, intrinsically this should decrease the amount of torque required to spin the cylinder but according to my math/formulas, the torque is also increased. So somewhere I have made an incorrect assumption that I need some help with. Thank you!
 
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I don't know all the math, but I think the torque applied to the flywheel increases because R increases, but the speed of rotation is reduced. Applying the same force at twice the radius increases the torque by 2x but the speed is reduced by half. (I don't know if the numbers are correct, but you get my point)

I think your mistake is that the amount of torque required to spin the cylinder stays the same, but the force changes since the larger radius gives you more torque per force input.
 
Hi - I think you might be tying yourself up in knots as this is a rotational movement and you're using linear mechanics.

F=ma in linear motion

F=Iw in rotational motion where I is the moment of inertia (integral of mass x radius from centre to outer edge of cylinder) and w is angular velocity in radians per second ( it is an acceleration as it involves continuous change of direction for each part of the cylinder - velocity is a vector so a change in either speed or direction is an acceleration).

Try it now - your paradox will disappear.
 
jafolkerts said:
Cylinder rolling resistance upon steel rollers (Coefficient of friction (\mu)) = 0.0024
That's not the coefficient of friction, it's the rolling resistance as you have stated.

jafolkerts said:
First, we need to calculate the force that is required to overcome the rolling resistance of the cylinders on the steel rollers:

Fc = (0.0024)(26,977.5 N) = 64.746 N
This is correct.

jafolkerts said:
I would now like to calculate the torque required to spin this cylinder by applying this force to the edge of the flywheel using this formula:
Is the cylinder or the flywheel doing the rolling on the steel rollers?

If it rolls on the cylinder, then the required torque is Fc x Rcylinder. The required force on the flywheel = Fflywheel = Fc x Rcylinder / Rflywheel .

If it rolls on the flywheel, then the torque needed is Fc x Rflywheel, as you have calculated. The torque is greater in this case, but the rate of rotation is slower.
 
Last edited:
jafolkerts said:
Here's the issue that I am having troubles with: if I increase the flywheel's diameter, intrinsically this should decrease the amount of torque required to spin the cylinder but according to my math/formulas, the torque is also increased. So somewhere I have made an incorrect assumption that I need some help with. Thank you!

I guess so.

It is true that if you need a given amount of torque, you'll have to apply less force to get that torque if you apply that force further away from the center.

But I'm not sure why you think it would take less torque to rotate an object with a larger diameter, since it's not true (having a larger diameter will give it a larger moment of inertia, making it harder to change the rotation rate).

And I'm not quite sure why that's relevant to this situation.

In this case, you have an example of where you're applying a given force (the force of friction) a certain distance away from the center to get a given amount of torque. If you apply that same force (the force of friction) further away from the center, that same force will get you more torque.
 

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