# Torsion constant of a bent spring

How do I find torsion constant (Kt) of a spring which is bent, as shown in the image below

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jack action
Gold Member
$$K_t= \frac{T}{\theta}= \frac{Fr}{\frac{x}{r}}= \frac{F}{x}r^2= Kr^2$$

Where $K$ is the linear stiffness of the spring and $r$ is the distance between the spring and the center of rotation.

Hello,
May be I wasn't clear in previous post. The spring is being rotated along its axis, while being kept in a curved position. In this case how will the torsion constant change ?

jack action