Torsion of rectangular cross section rotated at an angle?

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SUMMARY

The discussion focuses on calculating the polar moment of inertia for a rectangular cross section used as a torsion spring, specifically for a blade-type anti-roll bar. The user seeks to understand how to adjust the rectangular cross section by rotating it at an angle theta. It is established that the torsion constant J differs from the polar moment of inertia for non-circular sections, complicating stress calculations. The parallel-axis theorem can be applied by decomposing the shape into simpler components, such as rectangles, to facilitate the calculation of moment of inertia.

PREREQUISITES
  • Understanding of torsion mechanics and torsion springs
  • Familiarity with polar moment of inertia calculations
  • Knowledge of the parallel-axis theorem
  • Basic principles of structural engineering and material properties
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  • Research the calculation of the torsion constant J for non-circular cross sections
  • Study the application of the parallel-axis theorem in composite shapes
  • Learn about stress analysis in torsion springs
  • Explore the design principles of anti-roll bars in automotive engineering
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Mechanical engineers, structural analysts, and automotive designers interested in torsion mechanics and the design of non-circular cross-section components.

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I want to use a rectangular cross section to act as a torsion spring that can be adjusted. The idea is that the adjustment would be made via rotating the rectangular cross section about it's center at an angle theta. I've used parallel axis theorem before, but I don't think that is applicable here since it is just one shape. How can I calculate the polar moment of inertia so that I can then use other stress equations? If you're curious for what it's for, it's intended to be a blade type anti-roll bar.

Thanks for the help!
 
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The torsion of non-circular cross sections is way more complicated than for circular cross sections. That's why torsion springs and anti-roll bars are usually circular in cross-section.

The torsion constant J is no longer equal to the polar moment of inertia for non-circular sections, and the calculation of stress is also no longer a simple procedure.

http://en.wikipedia.org/wiki/Torsion_constant
 
The parallel-axis theorem can be used with one shape if you break that shape down to smaller, more elementary shapes. For example, an I-beam can be broken down into 3 rectangles and determining the moment of inertia of the flanges from the simple formula bh^3/12 will require the parallel-axis theorem since the rotation axis isn't at the center of mass of the object (which the formula assumes).
 

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