Calculating the Length of the Tortoise-Hare Race

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The tortoise runs at 0.1 m/s and the hare at 2.0 m/s, with the tortoise receiving a 2-minute head start. The tortoise wins by 0.2 meters, prompting the calculation of the race's length. The equations used include D - 0.2 = 2(t - 120) for the hare and D = 0.1t for the tortoise. The solution is confirmed as correct, indicating that the setup for calculating the race length is valid. The discussion emphasizes the importance of properly setting up equations to solve for distance in race scenarios.
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Homework Statement



A speedy tortoise can run with a velocity of 01m/s and a hare can run 2.0m/s . In a race , the hare gives the tortoise a 2- minute head start. The tortoise wins the race by a shell ( 0.2m ) . What was the length of the race ?

Homework Equations


D =v/t , 20minute = 120 sec .

The Attempt at a Solution


D = distance , t = time for tortoise to run , t1 for the time of hare to run
for hare , D-0.2=2(t-120)
and for tortoise , D= 0.1 t
is that corrected ?
 
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Anthonyphy2013 said:

Homework Statement



A speedy tortoise can run with a velocity of 01m/s and a hare can run 2.0m/s . In a race , the hare gives the tortoise a 2- minute head start. The tortoise wins the race by a shell ( 0.2m ) . What was the length of the race ?

Homework Equations


D =v/t , 20minute = 120 sec .

The Attempt at a Solution


D = distance , t = time for tortoise to run , t1 for the time of hare to run
for hare , D-0.2=2(t-120)
and for tortoise , D= 0.1 t
is that corrected ?

It is correct. Solve.


ehild
 
thanks so much
 
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