Tortoise vs. Hare Race: Length of Race Solved

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The discussion revolves around a race scenario involving a tortoise and a hare, where the tortoise runs at 10 cm/sec and the hare at 100 cm/sec but takes a 2-minute rest. The tortoise wins the race by 20 cm. To solve for the length of the race, participants suggest creating equations for the distances covered by both animals over time, factoring in the hare's rest period. By equating the distances, one can determine the total length of the race. This mathematical approach is essential for finding the solution.
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Can someone help me with this question? I am not sure where to go with it.

A speedy tortoise can run with a velocity of 10 cm/sec and a hare can run 10 times as fast. In a race, they both start at the same time, but the hare stops to rest for 2.0 minutes. The tortoise wins by a shell (20 cm). What was the length of the race?

thanks
 
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pelikon said:
Can someone help me with this question? I am not sure where to go with it.

A speedy tortoise can run with a velocity of 10 cm/sec and a hare can run 10 times as fast. In a race, they both start at the same time, but the hare stops to rest for 2.0 minutes. The tortoise wins by a shell (20 cm). What was the length of the race?

thanks

Welcome to PF.

Maybe write an equation that describes the distance the Hare goes (including the 120 sec pit stop) as a function of time and add the 20 cm he loses by and the distance the Tortoise goes with time and then set the two equations equal?
 

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