Total Energy of a Geosynchronous Satellite

AI Thread Summary
To calculate the total energy of a geosynchronous satellite with a mass of 1500 kg at a height of 325 km and an orbital speed of 5000 m/s, the relevant equations are kinetic energy (Ek) and potential energy (Ep). The kinetic energy is calculated using Ek = 0.5 * m * v^2, while potential energy is determined by Ep = m * g * h. There is confusion regarding the use of orbital velocity in these calculations, as it is assumed the satellite remains stationary relative to the Earth's rotation. The discussion indicates that the teacher likely expects the total energy to be calculated using the simplified formula Et = mgh, acknowledging that gravitational acceleration (g) varies with altitude. Ultimately, the total energy calculation must consider both kinetic and potential energy, despite the complexities of gravitational variation at higher altitudes.
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Homework Statement


Calculate the total energy of a geosynchronous satellite (one that orbits over a fixed spot) with a mass of 1500kg, orbiting Earth at a height of 325km with an orbital speed of 5000m/s

Homework Equations


ET=Ek+Ep
Ek=(0.5)(m)(v)^2
Ep=(m)(g)(h)

The Attempt at a Solution



Looking at the orbital velocity was confusing me, so I researched geosynchronous satellites. The orbital velocity is being used to keep it stationary, assuming the Earth is rotating at the same velocity. So it is not used in these calculations.

Now, in this lesson we have not learned the formulas of Ek= G(mp)(mo) /rp and
Ep= -G(mp)(mo)

Therefore, I bet the what the teacher wants is just Et=mgh . I would like to believe that it is not asking us to include the orbital energy.

But again Et is not a vectory quanitiy and orbital energy is possible.

Would the total energy in this case be

Et=(mo)(0.5)(5000m/s)^2 + (mo)(g)(h)
 
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mgh applies near the Earth's surface where g is essentially constant. Way out where the satellite is, g ain't yer usual 'g' anymore! :wink:
 
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