Calculating the Total Energy of a Geosynchronous Satellite in Orbit

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Homework Help Overview

The discussion revolves around calculating the total energy of a geosynchronous satellite orbiting Earth, specifically focusing on a satellite with a mass of 1500 kg at a height of 325 km. Participants are exploring the relevant equations and concepts related to orbital mechanics.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants are attempting to apply the equations for total energy, kinetic energy, and potential energy. There are questions regarding the correct orbital height and the mass to use in calculations. Some participants are also discussing the relationship between centripetal force and gravitational force.

Discussion Status

The discussion is active, with various attempts to clarify the calculations and assumptions involved. Some participants have provided insights into the necessary conditions for a geosynchronous orbit, while others are questioning the accuracy of the initial height and energy calculations. There is no explicit consensus yet, but productive dialogue is ongoing.

Contextual Notes

Participants are navigating potential confusion regarding the orbital height and the mass of Earth to use in their calculations. There are also references to external resources for clarification on geosynchronous satellites.

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Homework Statement


Calculate the total energy of a geosynchronous satellite (one that orbits over a fixed spot) with a mass of 1500kg, orbiting Earth at a height of 325km with an orbital speed of 5000m/s

Homework Equations


Et= Ek-Ep
Et= -1/2(GMem)/r


The Attempt at a Solution


im guessing the answer should be negative, using the mass of Earth being 5.98*10^24, but its wielding an incorrect answer constantly ,im getting Et= 8.9*10^10J ( i calculated radius being... r= radius of Earth + height= 6.7*10^6 m, am i suppose to use a different mass instead of the mass of earth, thank you
 
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how would you find orbital height? quite confused thank you for the help
 
At a geosynchronous orbit you can figure the required orbital velocity to match the Earth's rotation, one orbit every 24 hours. We want the centripetal force equal the force of gravity,

F = GmM/R^2 = mv^2/R
 
yes , its orbiting Earth at 325km or 3.25*10^5m
Et= kinetic + potential energy= (mv^2/r- GMem/r^2) is that correct?
 
sorry, kinetic is 1/2(mv^2)
 
Cudi1 said:
yes , its orbiting Earth at 325km or 3.25*10^5m
Et= kinetic + potential energy= (mv^2/r- GMem/r^2) is that correct?

Looks good except the potential energy goes as 1/r.
 
oh , so it would be Et= 1/2(mv^2) - (GMem/r) and thank you for the help
im getting the total energy is -1.82*10^12j
 

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