Total interior and exterior charge of a hollow sphere?

Click For Summary
SUMMARY

The total charge on the interior and exterior walls of a hollow conducting sphere with a +40nC point charge at its center is determined using Gauss's Law. The inner radius is R (10 cm) and the outer radius is 1.5R. According to Gauss's Law, the electric field E is given by E=Qenc/4πε0r², leading to the conclusion that the inner surface will have a charge of -40nC, while the outer surface will have a charge of +40nC, ensuring the sphere remains electrically neutral overall.

PREREQUISITES
  • Understanding of Gauss's Law
  • Familiarity with electric fields and charge distribution
  • Knowledge of charge density calculations
  • Basic concepts of conducting materials in electrostatics
NEXT STEPS
  • Study the implications of Gauss's Law in different geometries
  • Learn about electric field calculations for spherical conductors
  • Explore charge distribution in conductors under electrostatic equilibrium
  • Investigate the effects of external electric fields on charged conductors
USEFUL FOR

Physics students, electrical engineers, and anyone studying electrostatics and charge distribution in conducting materials.

KoontzyN
Messages
3
Reaction score
0

Homework Statement


A hollow conducting sphere has inner radius R and outer radius 1.5R. A +40nC point charge is placed at the center. What is the total charge on the interior and exterior walls of the sphere?

R=10cm

Homework Equations


Gauss's Law
σ = Qenc/A

The Attempt at a Solution


I'm not too sure where to start. I know Gauss's Law for a sphere is E=Qenc/4πε0r2 , but I don't know where to go from here.

I also know that to find the charge density σ = Qenc/A. Plugging in the knowns I get σ= 3.18*10^-7 C/m^2. I'm not sure if that relates to the problem at all. Any help is appreciated.

 
Physics news on Phys.org
You are not asked for charge density.

How does the charge on the outer surface compare with that on the inner surface?
Consider the field outside the sphere. How is that affected by the charges on the sphere?
 

Similar threads

Replies
23
Views
5K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
12
Views
2K
Replies
21
Views
4K
  • · Replies 12 ·
Replies
12
Views
8K
  • · Replies 18 ·
Replies
18
Views
5K
  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K