Total moment of shear stress about the center line of a cylinder

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SUMMARY

The total moment of shear stress about the center line of a cylinder is calculated by integrating the shear stress over the circumference. In this discussion, the shear stress of the inner cylinder is confirmed to be 405 Pa. The differential force, represented as dF, is derived from the shear stress (τ) multiplied by the differential area (L r_i dθ). Understanding the integration process around the cylinder's circumference is crucial for visualizing the total moment of shear stress.

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  • Understanding of shear stress and its applications in mechanics
  • Familiarity with cylindrical coordinates and integration techniques
  • Knowledge of differential area calculations in engineering contexts
  • Basic principles of moment and torque in physics
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http://postimg.org/image/onxjqc26l/

I have found the shear stress of the inner cylinder to be 405 Pa like in the solution
but I am having trouble visualizing the total moment of this stress about the center line.
I was wondering if someone could explain where that d(theta) in the moment expression comes from, possibly with a diagramthanks
 
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The d(theta) comes in because you have to integrate around the circumference of the cylinder. The force on a differential area of the cylinder is ##dF=\tau (L r_id\theta)##.
 

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