Total power contained in 10.0[cos(160.7*pi*t)]^4 (Fourier Series)

Jd303
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Homework Statement



Compute the power contained in the periodic signal x(t) = 10.0[cos(160.7*pi*t)]^4

Homework Equations


The Attempt at a Solution



Hey guys,
I have just started Fourier Series and am struggling with this one. Without writing all my calculations, -I start with inverse Euler formula.
-Then integrate x(t)*e^(-j*ω*k*t) with respect to t. From 0 to (To)
-Then consider the value of the final exponentials when k is an odd and even number.

However i calculate that the answer for ak for any value of k to be 15/4?

Once again I have only started Fourier recently so any direction would be much appreciated.
 
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Please show your work.

Another approach you might try is using trig identities to find the Fourier series.
 
Provided are my calculations in the attachment
-The function has already been converted using the inverse Euler formula
- σ is equal to 160.7*pi*t
- The fundamental frequency is 2*σ/(2*π)

-Anyway to calculate this equation is fine, inverse euler was just given as a suggestion to begin.
 

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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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