Train collision (linear kinematics)

AI Thread Summary
A passenger train traveling at 29 m/s is 360 meters behind a freight train moving at 6 m/s, with a driver reaction time of 0.4 seconds before deceleration begins. The initial separation between the trains is calculated to be 350.8 meters when deceleration starts. The equations set up for the passenger and freight trains lead to a calculated minimum deceleration of -0.703 m/s², which differs from an online solution of -0.754 m/s². The discussion reveals that the passenger train does not need to stop completely to avoid a collision; it must simply ensure it does not overtake the freight train. The key takeaway is that the final velocity of the passenger train relative to the freight train should be zero at the point of meeting to prevent a collision.
walking
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Homework Statement


A passenger train is traveling at 29ms^-1 and a freight train is traveling 360m ahead of it at 6ms^-1 in the same direction on the same track. The driver of the passenger train has a reaction time of 0.4s before he starts decelerating. What is the minimum deceleration to avoid colliding with the freight train?

Homework Equations


x-0=29t+0.5at^2
0=29+at
x-350.8=6t

The Attempt at a Solution


I tried solving this as follows but my answer is wrong according to a solution I found online. Where am I going wrong?

First I calculated that when the driver starts decelerating, the separation of the trains will be 350.8m. I then let the initial time be this point in time (ie when they are 350.8 apart) and I let x=0 at t=0. So initially, the passenger train is at x=0 and the freight train is at x=350.8. I let the time they meet be t and the displacement of both trains be x at this time. Also, the minimum deceleration would be if the passenger train stops exactly when they meet.

Based on this, I got the following equations:

For the passenger train we get two equations:
x-0=29t+0.5at^2
0=29+at (since it comes to a stop when they meet)

For the freight train:
x-350.8=6t

Solving these, I got a=-0.703, however the solution I found online (in a pdf document of solutions to the problems in Tipler/Mosca 5th edition; this problem is chapter 2 q96) gives -0.754.
 
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walking said:
Also, the minimum deceleration would be if the passenger train stops exactly when they meet.
Why would the passenger train have to stop at that point?
 
Doc Al said:
Why would the passenger train have to stop at that point?
I thought it would give the slowest rate of deceleration if it comes to a stop at the maximum displacement to avoid collision, ie right when they meet. Maybe my intuition is wrong?
 
walking said:
I thought it would give the slowest rate of deceleration if it comes to a stop at the maximum displacement to avoid collision, ie right when they meet. Maybe my intuition is wrong?
Yes, your intuition is wrong. What you want to ensure is that when they meet the passenger train doesn't overtake the freight train (and thus collide). But to do that, it doesn't have to stop dead. Hint: The freight train is moving.
 
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Another suggestion: Do everything in the rest frame of the freight train instead.
 
Orodruin said:
Another suggestion: Do everything in the rest frame of the freight train instead.
In which case the OP's intuition would indeed be correct - final velocity of train relative to freight train would be zero!
 
neilparker62 said:
In which case the OP's intuition would indeed be correct - final velocity of train relative to freight train would be zero!
Indeed.
 

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