Train on 4.4 Incline: Solving for Momentary Rest

AI Thread Summary
To solve for the time it takes for the last car of a train to come to rest while coasting up a 4.4-degree incline, the initial speed of 3.10 m/s needs to be broken down into its x and y components. The incline's angle indicates that it rises 4.4 meters for every 100 meters traveled horizontally. Kinematic equations can be applied to the vertical motion to determine the deceleration due to gravity acting on the incline. The discussion emphasizes the importance of understanding the incline's angle and the relationship between speed components. Ultimately, applying the correct kinematic equations will yield the time for the last car to momentarily stop.
Manni
Messages
42
Reaction score
0
A train is traveling up a 4.4 incline at a speed of 3.10 when the last car breaks free and begins to coast without friction. How long does it take for the last car to come to rest momentarily?

The way I approached it that I reduced the speed to its x and y components. But I don't know what kinematic equations to use that relate the those two dimensions. Help?
 
Physics news on Phys.org
By 4.4 incline, does that mean that the incline rises 4.4 meters for every meter that is traveled horizontally? Or vice versa?
 
It means that the train makes an angle of 4.4 degrees relative to a flat surface
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Friction direction change in a inclined circular bend (car on a road)
Replies
11
Views
1K
Block at rest on an inclined surface
Replies
36
Views
5K
Solving for a Train Without Knowing Mass
Replies
1
Views
2K
A train that is momentarily at rest, Newton's Laws
Replies
3
Views
4K
Train travelling uphill at s.7s degree incline, find friction coefficient
Replies
10
Views
9K
Kinematics Problem: Train braking and blocking an intersection
Replies
1
Views
1K
Two decelerating trains on a collision course
Replies
2
Views
2K
Vector force conceptual exercise help.
Replies
2
Views
3K
How far did the train travel before stopping after detaching a compartment?
Replies
3
Views
3K
How far does the train travel before the engine is ....
Replies
2
Views
2K

Hot Threads

Recent Insights

Back
Top