Train Stopping Time: Different Observers, Different Times?

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SUMMARY

The discussion centers on the relativistic effects observed when a train moving at 0.6c stops, as perceived by both an external observer and an observer on the train. The external observer sees the train's ends stop simultaneously, while the train observer notes that the light rays reach the ends at different times, leading to a discrepancy in the recorded stopping times. The conversation highlights the importance of Inertial Reference Frames (IRF) and the implications of Lorentz Transformation on the perception of time and length during the stopping event.

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  • #31
PeterDonis said:
This release of tension is not accompanied by a change in actual length in frame O, but it *is* accompanied by a change in the train's state of motion. The change in the train's state of motion causes a release of the tension in both frames.

Would you explain why? how does the change in the train state of motion release the coil tension despite there is no change in the length between its 2 ends?
 
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  • #32
adelmakram said:
how does the change in the train state of motion release the coil tension despite there is no change in the length between its 2 ends?

There is no change in *actual* length relative to frame O. The change in the train's state of motion changes its unstressed length, relative to frame O. As I noted in a previous post, the unstressed length of the train depends on the forces between its atoms; and the change in the train's state of motion, relative to frame O, changes those forces. Inter-atomic forces are electromagnetic in nature, and EM forces change when the state of motion changes. In other words, forces are frame-dependent.
 
  • #33
In the specific version, the actual length at the time of the train stop =unstressed length ( given the length contraction into the account). Numerically = 5000 feet in the example shown. As I understood, at the stop, the train unstressed length will not change too. Did I go wrong?
 
  • #34
adelmakram said:
the actual length at the time of the train stop =unstressed length ( given the length contraction into the account).

The actual length *after* the train stops equals the unstressed length. The actual length *before* the train stops is larger than the unstressed length. I'm not sure which one you mean by "the actual length at the time of the train stop".

adelmakram said:
As I understood, at the stop, the train unstressed length will not change too. Did I go wrong?

Yes. The train's unstressed length changes when the train stops.
 
  • #35
adelmakram said:
ghwellsjr said:
and in the "platform" frame, we might "explain" by saying that the Proper Length of the coil is 6250 feet originally and 5000 feet finally so it experiences compression.
You said that for the ground observer, he will not see any change in the train length of 5000 feet before and after stop according to your first diagram. So the compression wave which starts at A for the train observer should not be seen by the ground observer! at the time the train stops. If the ground observer has to see any compression, he should observe this force when the train starts moving. In this case the proper length of 6250 drops down to 5000 feet during moving.
It doesn't matter which frame we use to analyze or depict a scenario. They all will show that everything that any observer can actually see or measure is the same.

What I want to do now is show you how an observer riding at the rear (red) end of the train will measure the Proper Length of the train as it drops from 6250 feet at the beginning to 5000 feet at the end.

In order to do this, he will use a laser range finder which shoots a pulse of light to a reflector at the front (black) end of the train and how it measures the round-trip time for light to get there and back and divides that time interval by two and calculates how far light travels in that amount of time. For our scenario, I have defined the speed of light to be 1 foot per nanosecond (or 1000 feet per microsecond). Actually, the laser range finder also keeps track of when each light pulse was sent and when its reflection was received and it applies the calculation of the distance to the average of those two times. This holds to Einstein's second postulate that the light takes the same amount of time to get to a target as it takes for the reflection to get back, although Einstein only applied it to an inertial observer and I'm applying both during intervals when the observer is inertial and non-inertial.

We go back to the original spacetime diagram in post #3 except that I'm only showing the two ends of the train and the laser signals going between them. I had to extend the diagram at the beginning and the end to accommodate the laser signals and their echoes.

Here's the first diagram. The thin red lines going upwards to the right are some of the laser signals that the observer at the rear (red) end of the train sends out. I'm only showing the ones that hit the black dots representing 1-microsecond intervals of time at the front of the train. The thin black lines going upwards to the left are the echoes. I have marked in the times on the observer's clock when the signals were sent and received:

attachment.php?attachmentid=70114&stc=1&d=1401233004.png

The observer compiles a list of the sent and received times and averages them to determine the "time" for which the measurement applies. He also calculates one-half of the difference between those same two times (in microseconds) and puts down the distance (or length) in thousands of feet to the front of the train. Here is his list of measurements in the first two columns and his calculations in the last two columns:

Code:
Sent	Rcvd	Avg	1/2 of
Time	Time	Time	diff

0	12.5	6.25	6.25
1	13.5	7.25	6.25
2	14.25	8.25	6.25
3	15.25	9.25	6.25
4	17	10.5	6.5
5	19	12	7
6	21	13.5	7.5
8	22	15	7
10	23	16.5	6.5
12	24	18	6
14	25	19.5	5.5
16	26	21	5
17	27	22	5
18	28	23	5


And from that, he makes a spacetime diagram showing how the length of the train gets from 6250 feet to 5000 feet. Along the way, it gets longer and then gets shorter. Keep in mind that when the two ends of the train stop at the same time, the front of the train initially experiences compression and the rear of the train experiences tension as shown in the diagrams in post #11 but after all the vibrations dampen out, the Proper Length of the train ends up at 5000 feet:

attachment.php?attachmentid=70115&stc=1&d=1401233004.png

Now I want to show you that the observer makes exactly the same measurements and therefor makes exactly the same determination of the length of the train in the platform frame:

attachment.php?attachmentid=70116&stc=1&d=1401233004.png

Can you see that even though the time for the light to traverse to the target and the time for the echo to get back to the observer are completely different in this diagram, the observer still makes the same calculations because he is assuming that those times are always equal?

Now what about the platform observer? Well, he can apply exactly the same technique to determine his distances to the two ends of the train and then make the same space time diagram shown at the beginning of this post. Then he can do the same thing that we did and determine the Proper Length of the train as it comes to a stop.
 

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  • #36
For the platform observer, he will calculate the train length before and after stop to be equal to 5000 feet. In his case, he does not have to wait for the echo to calculate the distance because he is not attached to any end of the train. He can only multiply the time of the light takes to travel from one end to another by the difference between the speed of the light and the speed of the train in case the light rays goes in direction of the train and by the sum of both speeds in case the ray goes in the opposite direction of the train.

So again the question is: as long as there is no change on the length of the train before and after stop as seen by the platform observer, then there is no compression after the train stop. The phenomena that is seen by the train observer after the train stop is not seen by the platform one after the train stop. In other words, for the platform observer (the contracted length before the train stop - the true length after the train stop)=0
 
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  • #37
adelmakram said:
as long as there is no change on the length of the train before and after stop as seen by the platform observer, then there is no compression after the train stop.

Wrong. You are incorrectly equating "no change in actual length" with "no compression". That is not correct. It would be correct if reality were not relativistic; in non-relativistic, Newtonian mechanics, yes, for there to be "compression" (more precisely, release of tension), there has to be a change in actual length, because the unstressed length of an object in Newtonian mechanics does not change when the object changes its state of motion. But in relativity, that's no longer the case; an object's unstressed length *does* change when it changes its state of motion. So in relativity, there can be "compression" (or release of tension) when an object changes its state of motion, even if its actual length, with respect to a particular frame, does not change.

All this has been pointed out to you several times now, so there's no point in your continuing to contradict it and our continuing to point it out again. If you have no new arguments to present, then there's not much point in further discussion.
 
  • #38
adelmakram said:
For the platform observer, he will calculate the train length before and after stop to be equal to 5000 feet. In his case, he does not have to wait for the echo to calculate the distance because he is not attached to any end of the train. He can only multiply the time of the light takes to travel from one end to another by the difference between the speed of the light and the speed of the train in case the light rays goes in direction of the train and by the sum of both speeds in case the ray goes in the opposite direction of the train.
There are, of course, numerous ways to make measurements, but that is a side issue to the main one having to do with compression. I don't understand your method for the platform observer to measure the length of the train and I would be interested in your further clarifying it. But since we all agree on what the two observers determine the length of the train to be before and after stopping according to the two reference frames, let's focus on the compression issue right now.

adelmakram said:
So again the question is: as long as there is no change on the length of the train before and after stop as seen by the platform observer, then there is no compression after the train stop. The phenomena that is seen by the train observer after the train stop is not seen by the platform one after the train stop. In other words, for the platform observer (the contracted length before the train stop - the true length after the train stop)=0
I think maybe you are now using a definition of "compression" to be "a shortening of length". If so, then you are correct, for the platform IRF, the train does not change length and so there is no compression.

However, throughout this thread, you have used the terms "tension" and "compression" to refer to a force. Let me quote what I said in post #8:
ghwellsjr said:
In order for all parts of a train (or any object) to stop simultaneously according to a frame, there must be something like clamps set up all along the track which simultaneously stop the train (by preprogrammed timers) that bring all the parts to a halt (in that frame) and keep the different parts from expanding back to their natural length.

After the train stops, the train observer can get out of the train and look at the track to see if there are any clamps firmly constraining the train to its length of 5000 feet. The platform observer can hop off the platform and do the same thing.

Do you agree that there must be some sort of restraint on the train to keep its length at 5000 feet after stopping or are you maintaining that if the brakes were applied at the front and rear of the train simultaneously in the platform frame, then after all the vibrations settle down, there will be no lateral force between the wheels and the rails?
 
  • #39
PeterDonis said:
So in relativity, there can be "compression" (or release of tension) when an object changes its state of motion, even if its actual length, with respect to a particular frame, does not change.

All this has been pointed out to you several times now, so there's no point in your continuing to contradict it and our continuing to point it out again. If you have no new arguments to present, then there's not much point in further discussion.

But frankly speaking, I don`t see any answer yet to my question in your comments so far. You mentioned many times that there would be a force even there is no change in the length but you didn't prove that. From where this force came? How did the change in the state of motion cause a force that is not length- dependent? How if the matter is not related to a compression but to a simple dynamical system where it depends on the distance between the 2 ends and that distance changes in one frame and not in another?
 
  • #40
ghwellsjr said:
Do you agree that there must be some sort of restraint on the train to keep its length at 5000 feet after stopping or are you maintaining that if the brakes were applied at the front and rear of the train simultaneously in the platform frame, then after all the vibrations settle down, there will be no lateral force between the wheels and the rails?

Yes I agree about this restraint. But I don`t get the meaning of lateral force. Can you please elaborate more about your reasoning?
 
  • #41
adelmakram said:
ghwellsjr said:
Do you agree that there must be some sort of restraint on the train to keep its length at 5000 feet after stopping or are you maintaining that if the brakes were applied at the front and rear of the train simultaneously in the platform frame, then after all the vibrations settle down, there will be no lateral force between the wheels and the rails?
Yes I agree about this restraint. But I don`t get the meaning of lateral force. Can you please elaborate more about your reasoning?
Since you agree that there must be a restraint, then you agree that there is a lateral force (along the direction of the rails) between the rails and the wheels to keep the train from expanding back to about 6250 feet. Or, to put it another way, if there were no clamps restraining the length of the train, then even though the brakes are applied and the wheels stop turning, the wheels are ineffective in stopping the train simultaneously in the platform frame and they just slide on the rails until the train gets back near to its original Proper Length of 6250 feet (in the platform frame).
 
  • #42
ghwellsjr said:
Since you agree that there must be a restraint, then you agree that there is a lateral force (along the direction of the rails) between the rails and the wheels to keep the train from expanding back to about 6250 feet.

This reply makes me even more confused: however there 1 urgent issue and one cold issue:

The first urgent issue is: Does that mean that every object moving with an apparent contracted length relative to an observer is under natural compression that to be relieved when it comes to a rest. If so , this means that the train or the coil in this example was under compression from the very beginning relative to the platform observer. For if this would be the case, a compression force should have started from the beginning of the motion and stayed all the time not only at the end. It also raises an important question, is the length contraction a mechanical phenomena?The less urgent issue: you illustrated before that for the train observer attached to the rear end, he will measures that the train length gets longer and then gets shorter before all vibrations dampen down. Now, during the lengthen phase which the train length increases to 7500 feet, there would be no compression but rather tension for the train observer, but for the platform observer, the force, if any, has to be applied all the time to keep the train length equals to 5000 feet.
 
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  • #43
ghwellsjr said:
I think maybe you are now using a definition of "compression" to be "a shortening of length".

Which is *not* a correct definition, because, as I noted in a previous post, you can have "compression" (or release of tension, i.e., a change in the internal stress of the object) without any shortening of length in a particular frame. And it's clear that the OP really intends "compression" to mean "change in internal stress"; he is just incorrectly assuming that you can only have a change in internal stress if there is a change in length.
 
  • #44
adelmakram said:
You mentioned many times that there would be a force even there is no change in the length

More precisely, I said many times that there is a change in *unstressed length* even though there is no change in *actual length*. The change in unstressed length comes from a change in *internal* forces inside the object--i.e., the forces between its atoms--when its state of motion changes.

adelmakram said:
you didn't prove that.

I did not give a detailed proof because that would require constructing a detailed model of the object, atom by atom, including the internal forces between the atoms. However, I did give a sketch of how such a proof would go: internal forces between atoms are electromagnetic, and it's obvious from Maxwell's Equations that electromagnetic forces change when an object's state of motion changes.

adelmakram said:
From where this force came?

If you mean, where do the internal forces between the atoms come from, surely that's obvious: if they weren't there, the train would not hold itself together as a single object. It would just be a cloud of atoms flying around. So obviously there must be *some* force holding the atoms together. It turns out, when you look at the details, that that force is electromagnetic.

If you mean, where do the forces that change the train's state of motion come from, well, you're the one that specified the problem as involving a change in the train's state of motion, so if you don't know, how am I supposed to know? I was assuming, as was ghwellsjr, that brakes were applied at each end of the train.

adelmakram said:
How did the change in the state of motion cause a force that is not length-dependent?

The force doesn't have to be length-dependent; it just has to be motion-dependent, i.e., it has to change as the state of motion of the atoms in the train changes. Electromagnetic forces have that property; see above.

adelmakram said:
How if the matter is not related to a compression but to a simple dynamical system where it depends on the distance between the 2 ends and that distance changes in one frame and not in another?

What kind of dynamical system would have this property? Remember that in relativity, "distance" is frame-dependent, and the laws of physics can't be frame-dependent. So any correct relativistic force law can't have a force that depends on "distance".

Note carefully, however, that this does not mean forces themselves can't be frame-dependent; what can't be frame-dependent are the *laws* that the forces satisfy. So, for example, the law for electromagnetic forces are Maxwell's Equations and the Lorentz force law, and these are not frame-dependent. But particular forces that obey these laws *are* frame-dependent; the forces transform along with the fields that appear in the laws so that the same laws--the same equations--hold in every frame, with respect to quantities in that frame.
 
  • #45
adelmakram said:
I agree about this restraint.

I don't; at least, not with the version of the scenario we have been using, where there is zero stress in the train (and the coil) after it stops (relative to the platform). In that scenario, the restraint, which keeps the train's length at something different than its unstressed length, would have to be present *before* the train stops (relative to the platform).

If there is a restraint present after the train stops (relative to the platform), then the train (and the coil) must be under compression after it stops, and must have been under zero tension before it stopped (relative to the platform). I said many posts ago that that is also a valid scenario; but I didn't think it was the version we were discussing.
 
  • #46
adelmakram said:
Does that mean that every object moving with an apparent contracted length relative to an observer is under natural compression that to be relieved when it comes to a rest.

No, of course not. The only reason that happens in this scenario (and it's natural *tension*, not compression, if the stress is present before the train stops; I've pointed this out several times already) is because of the way you specified the scenario. You specified that, in the platform frame, the train's length does not change when it stops. *That* is what forces the change in stress in the train (either from tension to zero stress, or zero stress to compression).

adelmakram said:
is the length contraction a mechanical phenomena?

No. Changing an object's state of motion is a mechanical phenomenon. How the object's length changes, or doesn't change, relative to a particular frame, and how the internal stresses in the object change, or don't change, depends on how you change its state of motion.

adelmakram said:
The less urgent issue: you illustrated before that for the train observer attached to the rear end, he will measures that the train length gets longer and then gets shorter before all vibrations dampen down. Now, during the lengthen phase which the train length increases to 7500 feet, there would be no compression but rather tension for the train observer, but for the platform observer, the force, if any, has to be applied all the time to keep the train length equals to 5000 feet.

These are two different versions of the scenario again. If the train's total length is constrained, in the platform frame, to always be 5000 feet, then it can't lengthen and shorten in the train frame; it can only shorten. The vibrations ghwellsjr was describing cannot happen the way he described them in this case.
 
  • #47
PeterDonis said:
ghwellsjr said:
I think maybe you are now using a definition of "compression" to be "a shortening of length". If so, then you are correct, for the platform IRF, the train does not change length and so there is no compression.
Which is *not* a correct definition,
It certainly is one of the many correct definitions of compression according to dictionary.com.

PeterDonis said:
because, as I noted in a previous post, you can have "compression" (or release of tension, i.e., a change in the internal stress of the object) without any shortening of length in a particular frame. And it's clear that the OP really intends "compression" to mean "change in internal stress"; he is just incorrectly assuming that you can only have a change in internal stress if there is a change in length.
And that is the point I made in post #38. But if you think I was unclear, then thanks for the added clarity.
 
  • #48
PeterDonis said:
adelmakram said:
I agree about this restraint.
I don't; at least, not with the version of the scenario we have been using, where there is zero stress in the train (and the coil) after it stops (relative to the platform). In that scenario, the restraint, which keeps the train's length at something different than its unstressed length, would have to be present *before* the train stops (relative to the platform).

If there is a restraint present after the train stops (relative to the platform), then the train (and the coil) must be under compression after it stops, and must have been under zero tension before it stopped (relative to the platform). I said many posts ago that that is also a valid scenario; but I didn't think it was the version we were discussing.
In the opening post, there was no tension, no compression, no coil. It was a question about timing as indicated by the title of this thread and for which I gave an answer in post #3. After that, the OP introduced the coil and an "extra tension" as a result of the train stopping that he thought would result in the coil breaking. I pointed out that this was wrong but that there was a compression and that SR was inadequate to determine if the coil would break.

I also pointed out that it was not enough to have just the two ends of the train stop simultaneously in the platform frame but that there needed to be clamps all along the length of the train programmed by timers to make all points of the train stop simultaneously.

So to avoid these problems, I suggested two separated trains with the coil stretched between them to avoid the issue of having any stress in a single train while it was moving. I still don't why you think that "version" of the scenario is the one that we were discussing. I also don't understand how you think such a tension could be enacted in a train moving on the tracks.
 
  • #49
ghwellsjr said:
In the opening post, there was no tension, no compression, no coil.

No coil, yes. No tension or compression, no. The initial specification of the scenario *requires* that there is either tension in the train before it stops, or compression after. There is *no* way to physically realize the scenario as the OP specified it without one of those two being present. So even though the OP did not say so, the OP scenario *does* have either tension or compression.

ghwellsjr said:
It was a question about timing as indicated by the title of this thread and for which I gave an answer in post #3.

Yes, but as the subsequent discussion has made clear, the OP was really interested in more than just the timing. He was interested in the physical implications of "length contraction" (and part of the problem is that he's confused about the different possible meanings that term can have). Your spacetime diagrams implicitly contain the answers to those questions as well.

ghwellsjr said:
After that, the OP introduced the coil and an "extra tension" as a result of the train stopping that he thought would result in the coil breaking.

He thought he was introducing "extra tension"; but that's only because he didn't realize that his original specification of the problem already included tension (or compression), as above.

ghwellsjr said:
I pointed out that this was wrong but that there was a compression

That depends on whether we assume that the train is under zero stress after it stops (in which case it's under tension before it stops), or before it stops (in which case it's under compression after it stops).

ghwellsjr said:
SR was inadequate to determine if the coil would break.

Correct, you also need a material model of the coil.

ghwellsjr said:
I also pointed out that it was not enough to have just the two ends of the train stop simultaneously in the platform frame but that there needed to be clamps all along the length of the train programmed by timers to make all points of the train stop simultaneously.

This is true if you want every part of the train to stop simultaneously, yes, which is what the OP seems to have intended.

ghwellsjr said:
So to avoid these problems, I suggested two separated trains with the coil stretched between them to avoid the issue of having any stress in a single train while it was moving. I still don't why you think that "version" of the scenario is the one that we were discussing.

I don't. I think the one we were discussing is the OP's original scenario, with the assumption that the train is under zero stress after it stops. The OP never explicitly stated this, but I think that's what he originally had in mind (not realizing the full implications, of course). If the OP wants to specify a different assumption, that's fine. The real point is that the OP needs to understand *all* the implications of whatever specification he makes of the scenario.

ghwellsjr said:
I also don't understand how you think such a tension could be enacted in a train moving on the tracks.

It certainly wouldn't be easy to do; but I'm not the one that made up the scenario. :wink: One possible way would be to have an engine at each end of the train, with the front engine pulling forward and the rear engine pulling backward, and a frictionless track so that the center of mass of the train is moving inertially. Of course, in a real train, this wouldn't work at relativistic velocities because the train would be torn apart; we don't make trains out of materials that can sustain relativistic stresses. But in principle you could do it that way.
 
  • #50
ghwellsjr said:
It certainly is one of the many correct definitions of compression according to dictionary.com.

You're right, the statement I made was too strong. Your point in post #38 (with my clarification) is really what I was trying to say, and I should have just stuck to that.
 
  • #51
adelmakram said:
ghwellsjr said:
Since you agree that there must be a restraint, then you agree that there is a lateral force (along the direction of the rails) between the rails and the wheels to keep the train from expanding back to about 6250 feet.
This reply makes me even more confused:
If you hadn't specified that both ends of the train stop at the same time in the platform frame but instead if you had just said that the train came to a stop the way all trains come to a stop, by applying their brakes over a long period of time, then the length of the train would end up near 6250 feet. We can't say exactly because Special Relativity cannot address that issue, as I said before.

adelmakram said:
however there 1 urgent issue and one cold issue:

The first urgent issue is: Does that mean that every object moving with an apparent contracted length relative to an observer is under natural compression that to be relieved when it comes to a rest. If so , this means that the train or the coil in this example was under compression from the very beginning relative to the platform observer. For if this would be the case, a compression force should have started from the beginning of the motion and stayed all the time not only at the end. It also raises an important question, is the length contraction a mechanical phenomena?
No, as I indicated in post #16 and gave you three examples, Length Contraction is a coordinate effect, it has nothing to do with anything mechanical happening. When you take an inertial object, or a non-inertial object during intervals when it is inertial, and you transform the coordinates from the frame in which the object is at rest where its length is its Proper Length, to a frame in which the object is moving, the object is Length Contracted to its Proper Length divided by gamma, exactly. No stresses or anything mechanical is involved when you simply change to a different frame with different coordinates. Don't get Length Contraction mixed up with the change in length as a result of acceleration. This change in length is not predictable by Special Relativity but we often like to approximate it as being equal to the Proper Length divided by gamma. Indeed, if we really accelerated any object instantaneously (like you did in your scenario) it would be instantly destroyed. If we used a realistic acceleration, the diagrams would be close to a million times larger and be impossible to comprehend, not to mention, boring.

adelmakram said:
The less urgent issue: you illustrated before that for the train observer attached to the rear end, he will measures that the train length gets longer and then gets shorter before all vibrations dampen down. Now, during the lengthen phase which the train length increases to 7500 feet, there would be no compression but rather tension for the train observer, but for the platform observer, the force, if any, has to be applied all the time to keep the train length equals to 5000 feet.
Yes, I did mention vibrations but I shouldn't have because they have nothing to do with the length as determined by an observer. I should have said that the length determined by a non-inertial observer can fluctuate during the period of acceleration. I think this is what Peter was referring to at the end of post #46.

You should read again what Peter said in post #25:
PeterDonis said:
Length contraction is not well-defined relative to a given observer if the two ends of the train are in relative motion, with respect to that observer. That's because the train's "length" itself is not well-defined, relative to that observer, if the two ends of the train are in relative motion.

Bear in mind that length contraction, like "length" itself, is a derived phenomenon in relativity; it's not fundamental. The fundamental objects are the worldlines of the parts of the train, which are invariant curves in spacetime and can be described without even choosing a reference frame. Length contraction, time dilation, relativity of simultaneity, etc., are not necessary to describe the physics; the only reason we talk about them is that our minds are evolved to perceive things in these terms.

There is no standard definition for a non-inertial frame. I just used a particular definition that I like that produced the lengthening and then the shortening of the train before the non-inertial transients due to acceleration ended. And just to emphasize what Peter said, I will now show you what an observer at the front end of the train determines using exactly the same process as I used in post #35 so if you want to know the details of the process, read about them in that post.

Here is the diagram for the IRF in which the train starts off moving and ends up stopped:

attachment.php?attachmentid=70205&stc=1&d=1401611854.png

Here is the log of the data the observer takes and the calculations he makes:

Code:
Sent	Rcvd	Avg	1/2 of
Time	Time	Time	diff

0.5	13	6.75	6.25
1.5	14	7.75	6.25
2.5	15	8.75	6.25
3.5	16	9.75	6.25
4.5	16.5	10.5	6
5.5	17	11.25	5.75
6.5	17.5	12	5.5
7.5	18	12.75	5.25
8.5	18.5	13.5	5
9.5	19	14.25	4.75
10.5	19.5	15	4.5
11.5	20	15.75	4.25
12.5	20.5	16.5	4
13.5	21	17.25	3.75
14	22	18	4
14.5	23	18.75	4.25
15	24	19.5	4.5
15.5	25	20.25	4.75
16	26	21	5
17	27	22	5
18	28	23	5

Here is the diagram of the non-inertial reference frame he constructs from the log.

attachment.php?attachmentid=70206&stc=1&d=1401611854.png

Note that the train doesn't get longer, rather it shortens to less than 4000 feet and then lengthens back to 5000 feet.

And here is the diagram for the IRF in which the trains starts out at rest and ends up moving:

attachment.php?attachmentid=70207&stc=1&d=1401611854.png

Once again, the frame has no bearing on the measurements and observations that are made, including those of stress.
 

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  • #52
PeterDonis said:
What kind of dynamical system would have this property? Remember that in relativity, "distance" is frame-dependent, and the laws of physics can't be frame-dependent. So any correct relativistic force law can't have a force that depends on "distance".

Note carefully, however, that this does not mean forces themselves can't be frame-dependent; what can't be frame-dependent are the *laws* that the forces satisfy. So, for example, the law for electromagnetic forces are Maxwell's Equations and the Lorentz force law, and these are not frame-dependent. But particular forces that obey these laws *are* frame-dependent; the forces transform along with the fields that appear in the laws so that the same laws--the same equations--hold in every frame, with respect to quantities in that frame.

Here are 2 examples which I am just thinking about:

1) Consider a point charge located at the front end of the train and a magnetic field in the rear end where the magnetic field lines run perpendicular to the long axis of the train as shown in the figure. As the front end starts to move toward the rear end, a magnetic force will act on it and its direction will be determined by right hand rule. So, the point charge should move under the effect of this force in the upward direction, toward the roof of the train. Will that movement be observed in the platform observer?
2) How about gravitational force, how if there are 2 massive objects at both ends of the train. When the length shortens the force increase between them ( inverse square law), will this be the same for the platform observer?
 

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  • #53
adelmakram said:
1) Consider a point charge located at the front end of the train and a magnetic field in the rear end where the magnetic field lines run perpendicular to the long axis of the train as shown in the figure. As the front end starts to move toward the rear end, a magnetic force will act on it and its direction will be determined by right hand rule. So, the point charge should move under the effect of this force in the upward direction, toward the roof of the train. Will that movement be observed in the platform observer?
Transform the coordinates:
http://farside.ph.utexas.edu/teaching/em/lectures/node109.html

and transform the fields:
http://farside.ph.utexas.edu/teaching/em/lectures/node123.html

Then apply the Lorentz force law.

adelmakram said:
2) How about gravitational force, how if there are 2 massive objects at both ends of the train. When the length shortens the force increase between them ( inverse square law), will this be the same for the platform observer?
That requires general relativity where the gravitational force does not strictly follow an inverse square law. We should stick with EM phenomena until you have learned SR.
 
  • #55
adelmakram said:
Those transformation will not be applied in this case because the state of motion of 2 ends of the train are not the same for all reference frames.
Yes, they do apply. They apply any time that gravitational effects are not significant. The motion of the 2 ends of the train is not relevant.
 
  • #56
DaleSpam said:
Yes, they do apply. They apply any time that gravitational effects are not significant. The motion of the 2 ends of the train is not relevant.

Fine, So would you please show how the platform observer could explain the upward motion of the point charge?
 
  • #57
You should work it through on your own using the material I linked to above. It will be much more instructive for you that way.

Also, your brief description is not sufficiently clear for me to work it through without trying to guess what you had in mind.
 
Last edited:
  • #58
DaleSpam said:
You should work it through on your own using the material I linked to above. It will be much more instructive for you that way.

Also, your brief description is not sufficiently clear for me to work it through without trying to guess what you had in mind.

It is a difficult problem no matter what I have in my mind.
 
  • #59
When both ends of the train stop at the same time relative to the platform observer, the point charge will only move when a magnetic field changes in intensity. But the magnitude of that change and the resultant direction of the force acting on the charge is not clear for me to calculate.
 
  • #60
Are you familiar with matrices and linear algebra?
 

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