Train Velocity: Calculating Midpoint Velocity at Instant

  • Thread starter Thread starter mayurkhairnar
  • Start date Start date
  • Tags Tags
    Train Velocity
AI Thread Summary
To determine the midpoint velocity of a train when the engine has an initial velocity 'u' and the last coach crosses a pole at velocity 'v', basic kinematic equations can be applied. The midpoint velocity can be calculated as an average of the initial and final velocities of the train. Since the guard's coach is moving at 'v', it suggests that the velocity of the midpoint will be influenced by both 'u' and 'v'. The assumption that the midpoint velocity equals 'v' is incorrect without considering acceleration or deceleration. Therefore, the correct approach involves using the average of the two velocities to find the midpoint velocity at that instant.
mayurkhairnar
Messages
2
Reaction score
0
1. If a train engine is traveling with initial velocity 'u' and the guard's coach(last coach of the train) is found to cross a pole with velocity 'v', then what is the velocity of the midpoint of the train at that instant?
 
Physics news on Phys.org
mayurkhairnar said:
1. If a train engine is traveling with initial velocity 'u' and the guard's coach(last coach of the train) is found to cross a pole with velocity 'v', then what is the velocity of the midpoint of the train at that instant?

What have you tried so far?
 
I have not tried anything. This question is asked my brother. He is appearing in Competitive exam
 
try using basic equations like v=u+at. i think that v will be same.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top