Trajectory: integrating for position

AI Thread Summary
The discussion revolves around deriving the trajectory of a projectile under the influence of gravity while neglecting air resistance. Participants clarify that the initial velocity components can be expressed as Vocos(θ) for horizontal and Vosin(θ) for vertical motion. They emphasize the importance of integrating the equations of motion separately for horizontal and vertical directions, leading to the final trajectory equation. The conversation also touches on comparing this trajectory to one that includes air resistance, using Taylor series for simplification. The participants conclude that they have successfully derived the necessary equations for both scenarios.
  • #51
I actually did that FIRST, thinking I was doing part a, but I actually did b.

I think this question is basically done, I can show you my other section maybe?
They do basically match.
 
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  • #52
Oblio said:
I actually did that FIRST, thinking I was doing part a, but I actually did b.

I think this question is basically done, I can show you my other section maybe?
They do basically match.

Sure... go ahead and show it.
 
  • #53
y= (v_{yo} + v_{ter}x) / v_{xo} + v_{ter}\tau ln (1 - x / v_{xo}\tau)

I'll skip a simplification step unless its needed: Used taylor's series which allowed cancellations.

y=v_{yo}x / v_{xo} - x^2v_{ter}\tau / 2v_{xo}^{2}\tau^{2}
 
  • #54
as usual subscripts are superscripts...
 
  • #55
Oblio said:
y= (v_{yo} + v_{ter}x) / v_{xo} + v_{ter}\tau ln (1 - x / v_{xo}\tau)

I'll skip a simplification step unless its needed: Used taylor's series which allowed cancellations.

y=v_{yo}x / v_{xo} - x^2v_{ter}\tau / 2v_{xo}^{2}\tau^{2}

Not sure if that's right or not... what is \tau ? I don't know the answer... if you want I can try to work it out to see if I get the same thing...
 
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