Engineering Transfer Function and State Space Analysis of Op-Amp circuit

AI Thread Summary
The discussion focuses on deriving the transfer function and state space representation of a noninverting operational amplifier circuit. The user provides specific component values and equations for the circuit's impedances, Z1(s) and Z2(s), leading to the transfer function Vo(s)/Vi(s). The user expresses uncertainty about further evaluating the derived equations, particularly in getting everything under a common denominator to simplify the transfer function. The conversation suggests collaborating on the next steps for both the transfer function and state space analysis. The thread emphasizes the importance of careful manipulation of the equations to achieve the desired forms.
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Homework Statement



[PLAIN]http://imagizer.imageshack.us/v2/800x600q90/690/0tab.png
I'm asked to find the transfer function and then find the state space representation and seem to be stuck.

Homework Equations





The Attempt at a Solution



My textbook states that for a noninverting operational amplifier shown below

http://imagizer.imageshack.us/v2/800x600q90/10/zmir.png

\frac{V_{o}(s)}{V_{i}(s)} = \frac{A}{1 + frac{AZ_{1}(s)}{Z_{1}(s) + Z_{2}(s)}}

and for large A

\frac{V_{o}(s)}{V_{i}(s)} = \frac{Z_{1}(s) + Z_{2}(s)}{Z_{1}(s)}

For my circuit

[PLAIN]http://imagizer.imageshack.us/v2/800x600q90/690/0tab.png

I'll make the follow substitutions

R_{4} = 110 KΩ
C_{2} = 4 μF
R_{3} = 600 KΩ
R_{2} = 400 KΩ
C_{1} = 4 μF
R_{1} = 600 KΩ

Now then

Z_{1}(s) = R_{2} + (C_{1}s + \frac{1}{R_{1}})^{-1}
Z_{2}(s) = R_{3} + (C_{2}s + \frac{1}{R_{4}})^{-1}

Hence for my circuit the transfer function is

\frac{V_{o}(s)}{V_{i}(s)} = \frac{Z_{1}(s) + Z_{2}(s)}{Z_{1}(s)} = \frac{R_{2} + (C_{1}s + \frac{1}{R_{1}})^{-1} + R_{3} + (C_{2}s + \frac{1}{R_{4}})^{-1}}{R_{2} + (C_{1}s + \frac{1}{R_{1}})^{-1}}

I can rearrange and get

V_{o}(s)(R_{2} + (C_{1}s + \frac{1}{R_{1}})^{-1}) = V_{i}(s)(R_{2} + (C_{1}s + \frac{1}{R_{1}})^{-1} + R_{3} + (C_{2}s + \frac{1}{R_{4}})^{-1})
R_{2}V_{o}(s) + \frac{R_{1}}{C_{1}R_{1}s + 1}V_{o}(s) = R_{2}V_{i}(s) + \frac{R_{1}}{C_{1}R_{1}s + 1}V_{i}(s) + R_{3}V_{i}(s) + \frac{R_{4}}{C_{2}R_{1}s + 1}V_{i}(s)
L^{-1}(R_{2}V_{o}(s)) + \frac{\frac{1}{C_{1}}}{s + \frac{1}{C_{1}R_{1}}}V_{o}(s) = L^{-1}(R_{2}V_{i}(s) + R_{3}V_{i}(s)) + \frac{\frac{1}{C_{1}}}{s + \frac{1}{C_{1}R_{1}}}V_{i}(s) + \frac{\frac{1}{C_{2}}}{s + \frac{1}{C_{2}R_{4}}}V_{i}(s)
R_{2}V_{o}(t) + \frac{1}{C_{1}}L^{-1}(\frac{V_{o}(s)}{s + \frac{1}{C_{1}R_{1}}}) = (R_{2} + R_{3})V_{i}(t) + \frac{1}{C_{1}}L^{-1}(\frac{V_{i}(s)}{s + \frac{1}{C_{1}R_{1}}}) + \frac{1}{C_{2}}L^{-1}(\frac{V_{i}(s)}{s + \frac{1}{C_{2}R_{4}}})

I'm not sure how to evaluate this further
 
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R2Vo(s)+\frac{R1}{C1R1s+1}Vo(s)=R2Vi(s)+\frac{R1}{C1R1s+1}Vi(s)+R3Vi(s)+\frac{R4}{C2R1s+1}Vi(s)

I would get everything on one side of the equation under a common denominator. I'll do the left half of an equation.

\frac{R2(C1R1s+1)}{C1R1s+1}Vo(s)+\frac{R1}{C1R1s+1}Vo(s)=...


\frac{R2(C1R1s+1)+R2}{C1R1s+1}Vo(s)=...

You do the right half. Then you can get it in the standard form for a transfer function.

We'll address the state space work when you get there
 
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