Transfer-function form of OPAMP-circuit

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Discussion Overview

The discussion revolves around deriving the transfer function of a noninverting op-amp circuit with a first-order low-pass filter. Participants are attempting to express the transfer function in a specific form while addressing algebraic challenges and corrections to earlier calculations.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant presents the initial transfer function H(f) and expresses difficulty in transforming it into the desired form.
  • Another participant suggests combining Z2 and R1 to simplify the expression and encourages completing the algebra.
  • A later reply indicates that the initial math may contain errors and provides a method to adjust the numerator to achieve the desired form.
  • One participant expresses frustration over the time spent on the problem and indicates a lack of progress.
  • A final contribution mentions a teacher's assistance, correcting the approach to simplify the transfer function by adjusting the numerator and incorporating terms into the alpha constant.

Areas of Agreement / Disagreement

There is no consensus on the correct approach to derive the transfer function, as participants express differing views on the algebraic steps and corrections needed.

Contextual Notes

Participants reference specific components and their relationships, but there are unresolved mathematical steps and assumptions regarding the circuit's configuration and parameters.

Who May Find This Useful

Students and practitioners working on op-amp circuit analysis, particularly those interested in transfer function derivations and algebraic manipulations in electrical engineering contexts.

kasperrepsak
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I am given an opamp circuit (noninverting opamp with 1st order lowpassfilter).
Please view the attachment for the circuit.
I have to show that the transfer function H(f)=Uo/Us is of the form:

H(f)=α( 1 + j(f/f1)) / ( 1 + j(f/f2))Using basic circuit analysis I came to the following (already checked that its correct) transfer function:

H(f)=Uo/Us= (R4/(R3+R4) ) x (R1 + Z2)/R1

Where Z2 is the equivalent impedance of the capacitor C2 in parallel with the resistor R2.

So: Z2 = R2/(jωCR2+1)

After substituting this into my transfer-function equation i can't get it into form they want me to. Again:
How can I get H(f)=Uo/Us= (R4/(R3+R4) ) x (R1 + Z2)/R1 with Z2 = R2/(jωCR2+1) in the following form:

H(f)=α( 1 + j(f/f1)) / ( 1 + j(f/f2))

I tried many times. I am pretty good at algebra but i just can't seem to grasp this one. Could someone please help me out? This is very important to me. If someone feels like something isn't clear then please write it,ill do anything to make it more clear.
 

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Combine Z2 and R1. Everything you did otherwise is A-OK. So just finish the algebra.

(I will give you the answer but you realize that if you're going to learn anything from this you have to finish the problerm yourself.)

Ans: a = R1R4/[(R3+R4)(R1+R2)],
f1 = w1/2pi where w1 = R1R2C/(R1+R2)
f2 = w2/2pi where w2 = R2C.

That assumes I did the math right myself! :-p
 
I've tried many times. I'll try again with your answers. Thank you :)
 
I can't .. :/ I have spent so much time on this problem already it's too much..
 
A teacher at my uni helped me out.. Your math is incorrect. For anyone trying to figure out this problem, when you end up with an extra term R2/R1, then just divide the whole nominator by (1+ R2/R1) and incorporate the (1 +R2/R1) into the alpha constant to get the desired form. : ) Thanks for the help rude man. :)
 

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