Transfer of Heat: mass of liquid helium that boils?

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SUMMARY

The discussion centers on calculating the mass of liquid helium that boils away from a spherical container at 4.2 K, surrounded by a shield at 72.8 K, over a period of 19.2 hours. The net power (Pnet) was calculated using the Stefan-Boltzmann Law, yielding a value of approximately 0.315 W. The total heat (Q) was then computed as 21,787.37 J, leading to a mass calculation using the latent heat of vaporization of helium (2.1 x 104 J/kg). However, the final mass result was incorrect, indicating a potential error in the area calculation or the emissivity values used.

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Liquid helium is stored at its boiling-point temperature of 4.2 K in a spherical container (r = 0.251 m). The container is a perfect blackbody radiator. The container is surrounded by a spherical shield whose temperature is 72.8 K. A vacuum exists in the space between the container and shield. The latent heat of vaporization for helium is 2.1 x 104 J/kg. What mass of liquid helium boils away through the venting valve in 19.2 hours?


I have tried calculating the net Powere first withthe equation Pnet =e sigma (5.67*E -8) A(.251*.251*pi) ( T^4-Tenvirnment^4) this gives me
.315210793711 as my Pnet. then I plug it into the formula Q=Pt Q=P*69120 secs) = 21787.3700613. My last step is to plug it into Q=mLv which is my new specific heat divided by my liquid heat of vaoprization of helium which is 2.1*E4 I get 1.03749, which is incorrect. I am not sure where I am going wrong . should I be calculating separate Q values from the beginning with different e values?
 
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For one thing the area of a sphere is 4[itex]\pi[/itex]r2.

So one calculates the P (W) from the Stefan-Boltzmann Law - using the correct area.

Then with power * time = Q, and one can then use the latent heat to find the mass.
 

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