Transformation Matrix: Understanding Its Purpose and Properties

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A transformation matrix T can be singular, meaning its determinant is zero, which prevents it from having an inverse to map images back to their original objects. This occurs in cases where the transformation reduces the dimensionality of the objects, such as projecting onto a plane or line. While some definitions of transformation matrices imply they should be non-singular, this is not universally applicable. The key distinction lies in whether the transformation is defined to maintain dimensionality or not. Understanding these properties is crucial for correctly applying transformation matrices in linear algebra.
danago
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Given a transformation matrix T, which maps objects (x,y) to the image (x',y'). The inverse of T will map the image back to the object.

Just wondering, what happens if matrix T is singular i.e. det(T)=0? Then there is no matrix to map the images back to the object.

My teacher said that he thinks a transformation matrix will never be singular, but he wasnt 100% sure, so I am just wanting to confirm.

Thanks,
Dan.
 
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danago said:
My teacher said that he thinks a transformation matrix will never be singular, but he wasnt 100% sure, so I am just wanting to confirm.

Thanks,
Dan.

If, by "transformation matrix", you mean the matrix representation of a linear operator, then of course it can be singular. Think of the mapping A : x --> 0, for every x from the domain.
 
That depends on what you mean by "transformation". The usual definition in Linear Algebra is simply that L(au+ bv)= aL(u)+ bL(v), which includes transformations that do not have inverses.

On the other hand, if you require that the "transformation" change any n-dimensional object to another n-dimensional object, then it is non-singular.
A singular transformation, such as a projection onto a plane or line, will map n-dimensional objects into lower dimensionals objects and has no inverse.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

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