Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Transformer Capacitive Coupling

  1. May 4, 2014 #1
    I had a 4:1 single phase step-down transformer. Primary winding was provided the mains supply (225V) and output (secondary) was 57V. I was under the impression that capacitive coupling b/w primary and secondary was noticeable only in high-voltage transformers, and thus in this case (low voltage) the two windings would practically be electrically isolated.
    However, when I measured the voltage b/w each of the primary (P1, P2) and secondary (S1, S2) terminals, I got significantly large values:
    S1->P1: 204V
    S2->P1: 154V
    S1->P2: 6V
    S2->P2: 44V

    Are these values because of capacitive coupling?

    I tried modelling this situation (Please have a look at the attached image. The arrows above primary and below secondary show assumed polarity). Then I wanted to find out the values of x and y through simultaneous linear equations, using the above values. But the first problem was that the meter showed RMS values which couldn't be negative, and secondly, this method didn't turn out to be correct either because all the different equations actually boiled down to a single equation. Is my model correct? How can I find the values of x and y?
     

    Attached Files:

  2. jcsd
  3. May 4, 2014 #2

    berkeman

    User Avatar

    Staff: Mentor

    Doi you have a capacitance meter? That's the easiest way to measure the winding-to-winding capacitances. BTW, the Cww values give you common-mode coupling between windings, not differential-mode coupling.
     
  4. May 4, 2014 #3

    jim hardy

    User Avatar
    Science Advisor
    Gold Member
    2016 Award

    Capacitance meter would be great.
    If your DMM is so equipped...

    In your circuit analysis, what did you assume for impedance of your meter ?

    Try ten megohms, which if digital it probably is.

    Then try a 'poor man's thevenin' equivalent by placing maybe 10k ohms across your meter and reading voltage again.

    Now you should have two equations to work with for your two unknowns.

    Reason for 10k ohms instead of zero ohms as in real thevenin work is: there could be a short between the windings and you dont want to wreck your meter. If there is a winding to winding short the 10k resistor might quickly get very hot, so be careful.

    SO: Check for shorts with ohmmeter first.

    AND dont leave energized wires where tiny fingers can reach them. You know how curious kids are.
    So hide your power cord.
    old jim
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook