Transformer primary-to-secondary turn ratio problem

  • Thread starter Thread starter physics100000
  • Start date Start date
  • Tags Tags
    Ratio Transformer
AI Thread Summary
In a step-down transformer with a primary to secondary turn ratio of 4:1, the peak current in the secondary is 12 A. The relationship between the primary and secondary currents can be derived from the power conservation principle, where P1 = P2, leading to the equation (4/1) = (Ip/12 A). The user is confused about the relationship between current and voltage, questioning the application of Ohm's Law (V = IR) in this context. The discussion emphasizes the need to understand how current ratios relate to voltage ratios in transformers. Clarification on these relationships is sought to solve for the primary current.
physics100000
Messages
6
Reaction score
0

Homework Statement



A step down transformer has a primary to secondary ratio of 4:1. If the peak current in the secondary is 12 A, the peak current in the primary is what?


Homework Equations



Vp/Vs = Np/Ns


The Attempt at a Solution



(4/1) = (Ip/12 A)

what is the relation between I and V? (V= IR or V= IP does not seem to work).

thanks in advance!
 
Physics news on Phys.org
In an ideal transformer the power in the primary is the same as in the secondary, P1 = P2. You know that P = IV, so ...
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Transformer; make primary voltage x10 of the secondary voltage
Replies
4
Views
2K
How Do You Calculate Primary Current in a Step-Up Transformer?
Replies
2
Views
2K
Transformer question (between substation and home)
Replies
1
Views
1K
The efficiency of a transformer
Replies
5
Views
2K
Transformer and power question mutiple choice
Replies
7
Views
2K
What is the correct equation to solve this power and voltage problem?
Replies
18
Views
2K
Transformers and Electromagnetism
Replies
3
Views
2K
Calculating turns in a primary coil of a transformer
Replies
2
Views
3K
Calculating Current in Primary Coil: Where Does P = V^2/R Formula Come In?
Replies
8
Views
2K
Brightness of lamp connected to transformer
Replies
17
Views
4K

Hot Threads

Recent Insights

Back
Top