Translation and compression/expansion

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The discussion revolves around the order of transformations in the functions y=√x and y=√2x-5, specifically translation and compression. It clarifies that translating the graph 5 units to the right occurs before applying horizontal compression by a factor of 1/2, and vice versa. The distinction is made between transformations of the form f(nx+m) and nf(x)+m, emphasizing that the latter does not require caution. The correct interpretation of the function transformations leads to understanding that both approaches yield the same final graph. Overall, the sequence of transformations significantly affects the resulting function's graph.
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i have a question about translation and compression/expansion
y=√x ; y=√2x-5

how do u know u translate 5 units right first or horizontal compression by 1/2 first...?
 
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Y = 2(X^1/2) - 5

if i got that correct
 
Is that y=\sqrt{2} x-5 or y=\sqrt{2x}-5

??

Daniel.
 
Exactly the same. There's no difference.
If it involves f(nx+m), then you need to beware of it.
If it involves nf(x)+m, no aware should be made.
In this case, since not the first case, no aware.
 
If you simply replace x by x-5, the graph will be shifted 5 to the right.
If you replace x by 2x, you will horizontally compress the graph by a factor 2.

So, if you shift and then compress:
\sqrt{x} \rightarrow \sqrt{x-5} \rightarrow \sqrt{2x-5}

and if you compress and then shift:
\sqrt{x} \rightarrow \sqrt{2x} \rightarrow \sqrt{2(x-5)}
 
o..icic...thx
 
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