Why Do Wave Equations Use Sinθ and Cosθ Interchangeably?

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SUMMARY

Wave equations can utilize either sine or cosine functions interchangeably due to their harmonic nature. The equations y(x,t) = Asin(ωt+kx) and y(x,t) = Acos(ωt+kx) represent the same physical phenomena, differing only by a phase shift of π/2. This phase difference does not affect the calculation of properties such as wavelength and wave number, as the origin can be set arbitrarily in space. The general form of these equations is y(x, t) = A sin(ωt + kx + φ), where φ represents the initial phase.

PREREQUISITES
  • Understanding of harmonic functions in wave mechanics
  • Familiarity with wave properties such as wavelength and wave number
  • Knowledge of phase shifts in trigonometric functions
  • Basic grasp of mathematical notation used in wave equations
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  • Learn about the implications of phase shifts in wave mechanics
  • Explore the relationship between sine and cosine functions in harmonic analysis
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Saxby
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Why do some wave equations use sinθ and others cosθ?

Does it make a difference when calculating properties such as wavelength and wave number?

For example:
y(x,t) = Asin(ωt+kx)
y(x,t) = Acos(ωt+kx)
 
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Saxby said:
Why do some wave equations use sinθ and others cosθ?

Does it make a difference when calculating properties such as wavelength and wave number?

For example:
y(x,t) = Asin(ωt+kx)
y(x,t) = Acos(ωt+kx)

These are the equations of transverse progressive waves. They have sin or cos because they are harmonic in nature. Yes of course if you do not write the equation in form of harmonic functions will they really remain harmonic ? Not at all !

I am sure your textbook might be answering questions better than me.

Edit: CompuChip beat me to it! Saxby, I did not see your question clearly. Of course, whether you use sin or cos in harmonic function is your own choice. Cos is just shifted by phase difference of pi/2. Also it does not matter because you can set your own origin anywhere in space...
 
Last edited:
They are the same, the cosine is just a sine offset by \pi / 2:
\cos(x) = \sin(x + \pi / 2)

The most general form would be
y(x, t) = A \sin(\omega t + k x + \phi)
where \phi is some initial phase that determines y(0, 0).
Usually, however, problems are (or can be) setup such that y(0, 0) = 0 or y(0, 0) = A.
 
Thanks for your help guys :)
 

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