Trapezoidal Rule: Maximum error in approximation?

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SUMMARY

The discussion focuses on calculating the maximum error in the approximation of the integral ∫ from 0 to 3 of f(x)dx using the Trapezoidal Rule, specifically T4. The key equation for error estimation is |ET| ≤ (K(b-a)³)/(12n²), where K represents the upper bound of the second derivative f''(x). Given the constraints -2 ≤ f''(x) ≤ 1, the maximum error can be determined by setting K to 2, which provides a conservative estimate for the error bound.

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  • Understanding of the Trapezoidal Rule for numerical integration
  • Familiarity with error analysis in numerical methods
  • Knowledge of calculus, specifically second derivatives
  • Ability to interpret mathematical inequalities
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  • Explore numerical integration techniques beyond the Trapezoidal Rule
  • Investigate the implications of second derivatives on function behavior
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Jess Karakov
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Homework Statement


Suppose that T4 is used to approximate the ∫ from 0 to 3 of f(x)dx, where -2 ≤ f ''(x) ≤ 1 for all x. What is the maximum error in the approximation?

Homework Equations


|ET|≤ (K(b-a)^3)/(12n^2)

The Attempt at a Solution


So I know how to find the error of the trapezoidal rule using the above equation, but I do not understand how to find the maximum error in an approximation.
To find the max error I would find the max/mins of f ''(x), right? But I don't know how to do that when f(x) is not given
 
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Jess Karakov said:

Homework Statement


Suppose that T4 is used to approximate the ∫ from 0 to 3 of f(x)dx, where -2 ≤ f ''(x) ≤ 1 for all x. What is the maximum error in the approximation?

Homework Equations


|ET|≤ (K(b-a)^3)/(12n^2)

The Attempt at a Solution


So I know how to find the error of the trapezoidal rule using the above equation, but I do not understand how to find the maximum error in an approximation.
To find the max error I would find the max/mins of f ''(x), right? But I don't know how to do that when f(x) is not given

You can't. All you can do is find an upper bound on the absolute error, so your actual error may be a lot less than your bound. Just find an upper bound on ##|f''(x)|## over ##x \in [0,3]##.

Note: people hardly ever find best bounds by finding actual maxima of things like ##|f''(x)|##; typically, they are satisfied with decent bounds.
 
So K would just be 2?
 
Jess Karakov said:
So K would just be 2?

You tell me.
 
yes...:wink:
 

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