Trig Limits: Does x/sin(x) = 1 as x-->0?

ggcheck
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This isn't really a homework question--but just something I was thinking about while doing homework.

Since lim(sinx/x) as x--->0 = 1

does that mean that lim(x/sinx) as x--->0 = 1 ?
 
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yes, you can manipulate the x/sinx to sinx/x which will give you 1
 
cool, how is that done?
 
lim x/sinx = lim 1/(sinx/x) = 1/1 = 1
as x->0
 
oh wow, that waas a long time ago, forgot about that :o

haha, thank
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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