- #1
alejandrito29
- 150
- 0
Is correct the following procediment?
## A \sin (\omega t) = A \sin (\phi) \to \phi= \sin^{-1} \sin (\omega t )##
Is correct to say that ## \phi = \omega t## is oscillatory in this case ??
## A \sin (\omega t) = A \sin (\phi) \to \phi= \sin^{-1} \sin (\omega t )##
Is correct to say that ## \phi = \omega t## is oscillatory in this case ??