Triple integral depending on a parameter

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SUMMARY

The discussion centers on evaluating the triple integral \(\iiint (x^{2n} + y^{2n} + z^{2n})\,dV\) over the region defined by \(x^{2} + y^{2} + z^{2} \leq 1\). The participants explored both Cartesian and spherical polar coordinates, noting that while the Cartesian approach complicates the limits of integration, spherical coordinates simplify them, especially for \(n = 1\). A conjecture was proposed to derive the integral's value for general \(n\) using induction, with a specific formula provided for even \(n\) values. The integral for \(n = 1\) relates to the sum of the inertias of a sphere with unit density.

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Homework Statement



Find [tex]\iiint (x^{2n} + y^{2n} + z^{2n})\,dV[/tex] where the integral is taken over the region of 3D space where [tex]x^{2} + y^{2} + z^{2} \leq 1[/tex]

Homework Equations



The Attempt at a Solution



I tried doing this in Cartesian coordinates, but the limits of integration got very messy and I got stuck after doing the first integral. I also tried using spherical polar coordinates, and then the limits of integration are quite simple, but the integrand gets complicated, unless [itex]n = 1[/itex], in which case the integral is quite easy to do.

I then thought that, since the only case where this looks simple enough to do directly is [itex]n = 1[/itex], I could try to make a conjecture as to what the value of the integral is for general n and then try to prove it by induction. The problem with that, though, is that I don't see how to go from the case [itex]n = k + 1[/itex] to the case [itex]n = k[/itex].

Any ideas?
 
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I haven't tried it myself yet, and the wife wants the computer just now, but have you tried spherical coordinates? That would be the natural first choice. May or may not work...

[Edit later] I think you can work it with spherical coordinates using symmetry and the formula$$
\int_0^\frac \pi 2 \sin^n x\, dx =\int_0^\frac \pi 2 \cos^n x\, dx =
\frac{1\cdot 3\cdot 5\cdot\cdot\cdot(n-1)}{2\cdot 4\cdot 6\cdot\cdot\cdot n}\frac \pi 2 $$which is valid for ##n## even and ##n \ge 2##.
 
Last edited:
This integral covers the volume enclosed by a sphere with radius = 1. It can be broken up into the sum of its parts, since the integrand is a sum.

For n = 1, the integral will evaluate to the sum of the inertias of a sphere about the three coordinate axes, assuming a unit density for the sphere.
 

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