Trouble Graphing Multivariable Functions

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SUMMARY

The discussion focuses on graphing the multivariable function f(x,y) = 1/sqrt(1-x^2-4y^2). The domain is defined as D: x^2 + 4y^2 < 1, and the range is R: (0,1]. Participants express difficulty in sketching level curves and cross sections, particularly in determining the appropriate values for k when setting f(x,y) = k. The key takeaway is the necessity of selecting k such that 0 ≤ 1/k ≤ 1 to accurately represent the level curves.

PREREQUISITES
  • Understanding of multivariable calculus concepts, specifically level curves.
  • Familiarity with the function f(x,y) = 1/sqrt(1-x^2-4y^2).
  • Knowledge of domain and range in the context of multivariable functions.
  • Basic graphing skills for visualizing functions in two dimensions.
NEXT STEPS
  • Research techniques for sketching level curves for multivariable functions.
  • Learn about cross sections in multivariable calculus.
  • Explore graphing tools such as Desmos or GeoGebra for visualizing f(x,y).
  • Study the implications of domain restrictions on function behavior.
USEFUL FOR

Students and educators in multivariable calculus, mathematicians working with graphing techniques, and anyone seeking to understand the visualization of complex functions.

_Steve_
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So the function I'm working with is:

f(x,y) = 1/sqrt(1-x^2-4y^2)

First, they want me to find the Domain and Range, which I found to be:
D: x^2 + 4y^2 < 1
R: (0,1]
Then they want me to sketch level curves and cross sections, then sketch f(x,y)
I'm having trouble with the sketching, I understand the concept of level curves, but when I make f(x,y) = k I'm not quite sure where to go from here... Does anyone have any graphing tips that I could use? Thanks!
 
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i wouldn't mind some insight on this as well.
 
You know that 0 ≤ x2 + 4y2 because x2 & y2 are each non-negative.

∴ 0 ≤ x2 + 4y2 > 1

So to find level curves, you must choose k so that 0 ≤ 1/k ≤ 1 .
 

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