I Trouble Solving an Equation that has square roots on both sides

  • I
  • Thread starter Thread starter thatboi
  • Start date Start date
  • Tags Tags
    Roots Square
Click For Summary
To solve the equation A(-√(C²+4F₊) - C) = B(√(C²+4F₋) + C), the challenge lies in eliminating the square roots from both sides. The discussion reveals that by manipulating the equation and squaring both sides, one can simplify the problem, although it introduces additional complexity due to constants. The resulting polynomial form, αC⁴ + βC² + γ = 0, indicates that it can be approached using methods for solving quartic equations. Participants note that while the equation is complex, it remains solvable with careful algebraic manipulation. Overall, the equation presents a challenging but manageable problem for those familiar with polynomial equations.
thatboi
Messages
130
Reaction score
20
Hey all,
I am having trouble solving the following equation for C
$$A(-\sqrt{C^2+4F_{+}}-C) = B(\sqrt{C^2+4F_{-}}+C)$$
I don't know how to get ride of the square roots on both sides.
Any help would be appreciated, thanks!
 
Mathematics news on Phys.org
\begin{align*}
\sqrt{C^2+4F_{+}}&=D\sqrt{C^2+4F_{-}}+EC\\
C^2+4F_{+}&=D^2\left(C^2+4F_{-}\right)+E^2C^2+2DEC\sqrt{C^2+4F_{-}}\\
GC^2+H&=C\sqrt{C^2+4F_{-}}\\
G^2C^4+H^2+2GHC^2&=C^2(C^2+4F_{-})\\
\alpha C^4 + \beta C^2 +\gamma &=0
\end{align*}

Looks like some work to do because of the many constants, but doable.
 
  • Like
  • Informative
Likes topsquark, bob012345, thatboi and 1 other person

Similar threads

Replies
19
Views
3K
Replies
10
Views
1K
Replies
22
Views
2K
Replies
6
Views
3K
Replies
13
Views
2K
Replies
2
Views
2K