Trouble with Logarithmic Equations: Help Needed for 5 Questions

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The discussion revolves around solving specific logarithmic equations from a worksheet, with the user struggling on five particular questions. They present equations such as (logx)^{logx}-9=0 and log_{4}x+log_{5}x=8.7, seeking assistance. A response confirms the user’s approach to one problem, suggesting they apply similar logarithmic rules to tackle the others. The user successfully resolves all questions after receiving guidance on converting logarithmic forms and using quadratic equations. Overall, the thread highlights common challenges in understanding and solving logarithmic equations.
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I'm having a lot of trouble on this worksheet I have, I've got most of the 32 questions except for about 5. I won't type out all the laws of logarithms as I assume that anyone coming in here to help me already knows them. So here are my questions (By the way, I've done work for them I just won't show it because it seems like I'm stuck where I'm at regardless):

17.) Solve for x:
(logx)^{logx}-9=0

24.) Solve for x, accurate to 2 decimal places
log_{4}x+log_{5}x=8.7

26.) Simplify completely.
\frac{log_{a}x}{log_{ab}x}-\frac{log_{a}x}{log_{b}x}

32.) Simplify/solve for x.
ln^{2}x+lnx^{3}+2=0

33.) Simplify/solve for x.
\frac{e^{x}+e^{-x}}{2}=k

Thank you for the help, I'm sorry about asking so many questions I just am really struggling on this one.
 
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Ok I did 26 and got this:

\frac{log_{a}x}{log_{ab}x}-\frac{log_{a}x}{log_{b}x}

\frac{logx}{loga}(\frac{logab}{logx})-\frac{logx}{loga}(\frac{logb}{logx})

\frac{logab}{loga} - \frac{logb}{loga}

log_{a}ab - log_{a}b

log_{a}\frac{ab}{b}

log_{a}a

= 1

So I think I got 26, is that right?
 
I haven't checked your calculations, but that is the right approach. You can use the same idea to solve 24 (convert the logs to the same base)

With a judicious use of a another logarithm rule you can convert 32 to a quadratic equation in \ln x

Multiplication by a correctly chosen exponential function (and clearing the fraction by multiplying everything by 2) will convert the final one to a quadratic equation in e^x
 
Ok thank you, I have figured them all out now so it's good.
 
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