Troubleshooting Force Calculation Errors

AI Thread Summary
The discussion revolves around troubleshooting force calculation errors in electrostatics. The user is consistently getting incorrect results for the forces acting on charges, specifically reporting values of 209 and 28.5 that are significantly off from expected results. Key issues identified include a potential typo in the force equations and the need to correctly apply sign conventions for forces. The user realizes that they miscalculated distances and made a sign error in their equations. Ultimately, correcting these mistakes is crucial for achieving accurate force calculations.
r-swald
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Homework Statement
Three point charges lie along a straight line as shown in the figure below, where q1 = 6.60 µC, q2 = 1.42 µC, and q3 = -2.04 µC. The separation distances are d1 = 3.00 cm and d2 = 2.00 cm. Calculate the magnitude and direction of the net electric force on each of the charges. I attached the picture of it below.
Relevant Equations
Equation: F = k|q1||q2| / r^2
I attempted this a few times but keep getting the same wrong answer...
Converted the values:
q1 = 6.6E-6
q2 = 1.42E-6
q3 = -2.04E-6
d1 = .03m
d2 = .02m

Calculation for force on 1
F1 = - F12 + F13 = - (9E9*6.6E-6*1.42E-6 / .03^2) + (9E9*6.6E-6*2.04E-6 / .02^2)

(I used negative for F12 to account for the charges repelling.)
The answer I got for this one was 209 and it says it differs more than 100%!

I did likewise with the second and got 28.5 and that was off by more than 10%. I don't think I did anything different for these, but I'm not sure. Please help! And thanks in advance!
 

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Welcome to the PF. :smile:
r-swald said:
Calculation for force on 1
F1 = - F12 + F13 = - (9E9*6.6E-6*1.42E-6 / .03^2) + (9E9*6.6E-6*2.04E-6 / .02^2)
Q1 is the left-hand charge, so the distance to Q3 is not just 2cm...
 
Awesome! got it. I didn't even think about that, now I Just have to figure out what I did wrong with the other one
 
Yeah so the second one I'm still getting wrong, it's probably something just as silly 🤔
F2 = F13 - F23 = (9E9*61.42E-6*6.6E-6 / .03^2) - (9E9*1.42E-6*2.04E-6 / .02^2)
I'm getting 28.54 for this and still saying I'm 10% off.
 
r-swald said:
F2 = F13 - F23 = (9E9*61.42E-6*6.6E-6 / .03^2) - (9E9*1.42E-6*2.04E-6 / .02^2)
I think you have a typo F13 should be F12, right? And I'd use sign convention where forces to the right on a charge are positive (positive x-axis), and forces to the left are negative. Maybe check the signs in that equation...? :smile:
 
berkeman said:
I think you have a typo F13 should be F12, right? And I'd use sign convention where forces to the right on a charge are positive (positive x-axis), and forces to the left are negative. Maybe check the signs in that equation...? :smile:
Also, there's an extra digit 6 in there (61.42).
 
Oh yeah, it was a sign problem. Thank you!
 
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