True or False, Parallel Axis Theorum

  • Thread starter Thread starter NoobeAtPhysics
  • Start date Start date
  • Tags Tags
    Axis Parallel
AI Thread Summary
The parallel axis theorem is confirmed as true, as it allows for the calculation of an object's moment of inertia about arbitrary axes if the moment of inertia about a perpendicular axis through the centroid is known. There is some confusion regarding the terms "parallel axis" and "arbitrary axis," but they are not the same. The discussion highlights the importance of careful reading, as a misinterpretation of "perpendicular" as "particular" could lead to errors. Overall, understanding the theorem is crucial for solving related problems accurately. The conversation emphasizes the need for clarity in terminology when tackling physics concepts.
NoobeAtPhysics
Messages
75
Reaction score
0

Homework Statement



I am doing an assignment where I have this (easy) true/false question.

The parallel axis theorem can be used to find moments of inertia of an object about arbitrary axes, provided the moment of inertia about a perpendicular axis through the centroid of the object is known.

Homework Equations



T=rf

The Attempt at a Solution



Ok, by definition this is true. And from what I understand this is what the parallel axis theorem does. I am reviewing the concept in my textbook.

But I only have one try for this.. it would be great if I could get some re-enforcement for my answer!
 
Physics news on Phys.org
Is a "parallel axis" the same as an "arbitrary axis"?
 
  • Like
Likes 1 person
NoobeAtPhysics said:
I am doing an assignment where I have this (easy) true/false question.

The parallel axis theorem can be used to find moments of inertia of an object about arbitrary axes, provided the moment of inertia about a perpendicular[/color] axis through the centroid of the object is known.
true, false, trick, or mistake ...
 
  • Like
Likes 1 person
wow i am dumb
 
Well I read "perpendicular" as "particular" - you have to watch those.
That was probably the one you were supposed to notice.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top