Trying to find mass given force, distance, and time.

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To find the mass of the block of ice, the correct approach involves using the formula F = m*a, where acceleration must be calculated using the distance and time given. The user initially misapplied the formula by using average speed instead of deriving acceleration from the standard equations of motion. For part B, the next steps involve determining the block's velocity at the end of the initial 4.80 seconds to calculate its subsequent motion. The discussion emphasizes the importance of correctly applying physics equations to solve for mass and distance. Understanding these concepts is crucial for accurately addressing the homework problem.
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Homework Statement



A dockworker applies a constant horizontal force of 70.0 N to a block of ice on a smooth horizontal floor. The frictional force is negligible. The block starts from rest and moves a distance 11.0 m in a time 4.80 s

Homework Equations


A)What is the mass of the block of ice?
B)If the worker stops pushing at the end of 4.80 s, how far does the block move in the next 4.20 s?


The Attempt at a Solution


A)F=m*a, 70.0=x*11.0/4.80
70.0/(11.0/4.80)=x, x=30.5 which was wrong.
B)I have absolutely no idea where to start or what to do on this part.
 
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welcome to pf!

hi jad6016! welcome to pf! :wink:
jad6016 said:
A)F=m*a, 70.0=x*11.0/4.80

no, you've used a = distance/time, which is wrong …

use one of the standard constant acceleration equations to find a :smile:
 
find first the acceleration
derive the d=vit+1^2at^2
that's what i think
 

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