Trying to fix a simplification issue for a general range formula

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The derived formula for the range of a projectile in a vacuum from a height h is R=(vcosθ/g)[vsinθ+sqrt((vsinθ)^2+2gh)]. A discrepancy arises when h=0, leading to an indeterminate form of 0/0. To resolve this, one should take the limit as h approaches 0, which correctly yields the familiar range formula sin(2θ)/g. The discussion highlights the importance of understanding limits in calculus to avoid misinterpretations of mathematical expressions. Acknowledging the discontinuity clarifies the situation and reinforces the need for careful analysis in physics equations.
FallenLeibniz
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So I have derived a formula for the range of projectile in a vacuum fired from an arbitrary height h from above the ground as the following...

R=(vcosθ/g)[vsinθ+sqrt((vsinθ)^2+2gh)]Now it seems all well and good, but when I try to play with it by multiplying the RHS by the congugate term over the conjugate term (i.e. multiplying by one), I keep coming up with the 2gh factor on top which if h=0 leads to a discrepancy between the two. Can anyone help reconcile this? Note that all factors in the equation are positive values. I can provide a derivation of this equation later if neccessary, but am late to be somewhere and so I must do it later.
 
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It's not there's a discrepancy. If you plug in h = 0 you will 0/0, which is indeterminate. So the right thing to do is take the limit as h tends to 0 from above, and that will give you sin(2θ)/g, as before.
 
Ok, I see the discontinuity now. I feel horrifically blind now.
 
Thank you.
 
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