Trying to understand weather balloons better (ideal gas law)

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SUMMARY

This discussion centers on the application of the ideal gas law, represented as (P1V1)/T1 = (P2V2)/T2, to understand the behavior of weather balloons. Key parameters include P1 as sea level pressure (1 atm), V1 as the initial gas volume, T1 as ground temperature, P2 as pressure at flight altitude, V2 as the balloon's maximum volume, and T2 as the temperature at altitude. Participants emphasize the importance of considering ambient atmospheric pressure and the tension in the balloon fabric, which affects internal pressure. Additionally, they discuss the need for pressure versus altitude formulas to determine volume changes at different heights.

PREREQUISITES
  • Understanding of the ideal gas law (PV=nRT)
  • Familiarity with atmospheric pressure concepts
  • Knowledge of buoyancy principles in lighter-than-air gases
  • Basic grasp of temperature variations with altitude
NEXT STEPS
  • Research "pressure versus altitude formulas" for weather balloons
  • Explore "how temperature decreases with altitude" in atmospheric science
  • Investigate "buoyancy calculations for lighter-than-air gases"
  • Study "the effects of tension on balloon pressure" in material science
USEFUL FOR

Aerospace engineers, meteorologists, students of physics, and hobbyists interested in ballooning and atmospheric science will benefit from this discussion.

amwest
Here's my understanding...
(P1V1)/T1 = (P2V2)/T2
P1 = starting pressure, typically sea level pressure which is 1atm.
V1 = Starting volume of the gas inside your balloon.
T1 = starting temperature, temperature at ground level.

P2 = final pressure, this should be the pressure at your flight altitude.
V2 = final volume, should be 100% of balloon capacity.
T2 = final temperature, temp at flight altitude.
Now I'm trying to understand this from a lighter than air gas standpoint, so...
Do i assume that:
P1, T1 are what i stated above, and do i assume that P2, T2 are proportional, if the gas isn't heated by a secondary source such as a hot air balloon?

Thanks in advance, will post further questions once these are validated or corrected!
 
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amwest said:
Here's my understanding...
(P1V1)/T1 = (P2V2)/T2
P1 = starting pressure, typically sea level pressure which is 1atm.
V1 = Starting volume of the gas inside your balloon.
T1 = starting temperature, temperature at ground level.

P2 = final pressure, this should be the pressure at your flight altitude.
V2 = final volume, should be 100% of balloon capacity.
T2 = final temperature, temp at flight altitude.
Now I'm trying to understand this from a lighter than air gas standpoint, so...
Do i assume that:
P1, T1 are what i stated above, and do i assume that P2, T2 are proportional, if the gas isn't heated by a secondary source such as a hot air balloon?

Thanks in advance, will post further questions once these are validated or corrected!
Temperature will be the ambient atmospheric temperature. Pressure will be the pressure that the balloon fabric can support and will be at least ambient atmospheric pressure. To determine whether the balloon will have positive buoyancy at a given T, P and V, what other parameter will you have to take into account (hint: apply ideal gas law)?

AM
 
The weight of the gas?
 
Andrew Mason said:
Pressure will be the pressure that the balloon fabric can support and will be at least ambient atmospheric pressure.
AM

i understand that the pressure has to be low enough to not pop the balloon. What do you mean by at least ambient atm pressure?
 
amwest said:
What do you mean by at least ambient atm pressure?
I think the point here is that the pressure inside the balloon will be slightly higher or at least equal to the ambient pressure outside the balloon, depending on tension in the balloon's surface.

If there wasn't a limit on how much the balloon could expand (about 100 to 1 volume wise), a hydrogen filled weather balloon could reach the outer layer of atmosphere, above low orbiting objects.
 
rcgldr said:
I think the point here is that the pressure inside the balloon will be slightly higher or at least equal to the ambient pressure outside the balloon, depending on tension in the balloon's surface.

If there wasn't a limit on how much the balloon could expand (about 100 to 1 volume wise), a hydrogen filled weather balloon could reach the outer layer of atmosphere, above low orbiting objects.

ok that makes sense.

So basicly a balloon is limited by:
V1 amount of gas needed to take off
then
V2 gas volume is maxed out at whatever altitude.
 
So if i had V1 = 1m^3 of hydrogen weight of 0.0899kg/m^3
how do i determine what its V2 would be at different heights?
 
amwest said:
how do i determine what its V2 would be at different heights?
The unknown is how much the pressure inside the balloon is affected by the tension in the balloon. You could assume zero tension and then assume pressure inside and outside the balloon is the same. You'll need to find pressure versus altitude forumulas / tables (wiki might have this).
 
rcgldr said:
The unknown is how much the pressure inside the balloon is affected by the tension in the balloon. You could assume zero tension and then assume pressure inside and outside the balloon is the same. You'll need to find pressure versus altitude forumulas / tables (wiki might have this).

ok I've looked and found a few tables but not very complete and I've read that the tables are exponential but haven't found a fomula.
 
  • #10
amwest said:
ok I've looked and found a few tables but not very complete and I've read that the tables are exponential but haven't found a fomula.
Try http://hyperphysics.phy-astr.gsu.edu/hbase/kinetic/barfor.html#c1" If you want to factor temperature into it, you will have to find how temperature decreases with altitude.

AM
 
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