Tubular shaft undergoes torsion

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SUMMARY

The discussion focuses on calculating the maximum torque that can be applied to a tubular shaft subjected to torsion, specifically a steel shaft with an outside diameter of 50mm and an inside diameter of 25mm. The maximum shearing stress must not exceed 70MPa. The relationship between shear stress, torque, and the polar moment of inertia is defined by the equation τ = Tc/J, where τ is the maximum shear stress, T is the maximum torque, and c is the outside radius. The polar moment of inertia is calculated using J = (π/2)(co^4 - ci^4), where co and ci are the outside and inside radii, respectively.

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For a system where a tubular shaft undergoes torsion, the maximum shearing stress in the steel shaft must not exceed 70MPa. The outside diameter of the tubular shaft is 50mm and the inside is 25mm
How do i determine the maximum torque that can be applied to the shaft?
 
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The max shear stress occurs on the cross-section at the outer wall. The general torque equation is

[tex]\tau[/tex] = [tex]\frac{Tc}{J}[/tex]

where [tex]\tau[/tex] in this case is the max shear stress, T is the max torque, and c is the outside radius.

J is the polar moment of inertia: J = [tex]\frac{\pi}{2}[/tex] (co4 - ci4).

co =outside radius
ci = inside radius
 

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