Two 1.0-g beads are charged .?

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SUMMARY

The discussion centers on calculating the magnitude of charge on two equally charged 1.0-g beads placed 5.0 cm apart, which accelerate at 150 m/s². The user correctly identifies the need to apply Newton's second law (F=ma) to determine the force acting on the beads, using the given acceleration rather than gravitational force. The appropriate formula to find the charge is Coulomb's law, expressed as q² = Fr²/k, where F is the electrostatic force, r is the distance between the charges, and k is Coulomb's constant.

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Two 1.0-g beads are charged ...?

Hi, I have never posted before but have seen great help given to people who are confused. I would really appreciate help on this question if possible.

"Two 1.0-g beads are charged equally and placed 5.0 cm apart. When released,
they begin to accelerate at 150 m/s2. What is the magnitude of the charge on each
bead?"

I am pretty sure I know how to do this question with the equation; (q2=Fr2/k), but I am not too sure if I use gravity or acceleration to find the force. F=ma. I think I would use acceleration since it is given in the question.

Any help would be greatly appreciated. Thanks.
 
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Assume that the only force acting is electrostatic attraction (ignore gravity, friction, etc.). So just use Newton's 2nd law to figure out the force and then apply Coulomb's law, just as you stated.
 
Thank you very much for your help...and quick response! I understand.
 

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