Two blocks and two pulleys pulley system

  • Thread starter Thread starter disruptors
  • Start date Start date
  • Tags Tags
    Assignment
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
6 replies · 3K views
disruptors
Messages
17
Reaction score
1
Hey ppl, sorry I was just wondering if anyone knew how to do the question i posted earlier(TWO BLOCKS AND TWO PULLEYS), as I have to submit it and cannot figure it out still!?

Thanks...
 
Physics news on Phys.org
can you post a picture of it. I'm having trouble picturing this system.
 
here's the pic, thanks
 
where? I don't see it as part of your post
 
oh sorry tiger, its okay i had to submit it, thanks for your time...i can't get the pic up for some reason..
 

Attachments

  • pulley pic.jpg
    pulley pic.jpg
    6.1 KB · Views: 564
  • Like
Likes   Reactions: Delta2
never mind must have been my browser
 
well how did you do the first part? it looks right to me. you did:

[tex]\sum{F} = ma[/tex]

always always ALWAYS start with this over and over again (or at least try to strat with this). The right hand side will have only ma or 0 that's all it will ever have ( and zero is a particular case of ma--when it is not accelarating, that is, not moving, or constant velocity) The left hand side just sums your forces. So after picking your postitive and negnative on your x and y-axis (always do this too) and drew your free body diagram (I hop you did this) you must of did:

[tex]T + T = m_2a_2[/tex]

And then you solved for T

Now for the next part do the same thing

1) Draw FBD
2) [tex]\sum{F} = ma[/tex]
3) [tex]T - m_1g = m_1a_1[/tex]

And then solve for [tex]a_1[/tex] in terms of everything else they gave you
 
  • Like
Likes   Reactions: Delta2