Two Blocks | Same Kinetic Energy (KE) Calculation

AI Thread Summary
The discussion revolves around a homework problem involving two blocks with the same kinetic energy and the relevant equations for work, force, and kinetic energy. The original poster expresses confusion about how to delete their post after realizing they solved the problem. Other participants suggest editing the post within a 24-hour window or creating a new post to indicate they no longer need assistance. The conversation remains focused on the technical aspects of the homework and the process of managing forum posts. Overall, the thread highlights the importance of community support in resolving academic queries.
soupastupid
Messages
34
Reaction score
0

Homework Statement



the force is given as F
the distance pushed is given as D

Homework Equations



W= F*d
F=ma
KE = 1/2 mv^2

The Attempt at a Solution



the blocks have the same kinetic energy
 
Last edited:
Physics news on Phys.org
how do i delete this?
 
soupastupid said:
how do i delete this?

Hi soupastupid! :smile:

Either edit it (I think there's a 24 hours edit window), or make another post, to say "never mind … i got it!" :smile:

(same with your other one … :wink:)
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top