- #1
leprofece
- 241
- 0
the intensity of the iluminacibn is directly proportional to the source intensity and inversely proportional to the square of Ia distance to the source. If two light bulbs are 16 cm of distance and one intensity of them is 4 times greater than the other, on which point of the line including Ia combined strength of the two foci is minimal?.
Remenbering
That I = ksin (f)/d2
and sin (h/d)
and d2= r2+h2
How must I organize this?? I tried with two triangles but i did not get the answer
Answer is = to 16/(1+cubic root of 4) from the more intesity bulb
Remenbering
That I = ksin (f)/d2
and sin (h/d)
and d2= r2+h2
How must I organize this?? I tried with two triangles but i did not get the answer
Answer is = to 16/(1+cubic root of 4) from the more intesity bulb