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Coco12
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Homework Statement
The electric field intensity at a point between two large parallel plates is 4.8 × 102
N/C. What does the electric
field become, as a result of each of the following changes, considered separately (the plates are isolated),
(a) when the distance between the plates is halved
when the plates are connected together by a conducting wire
Homework Equations
E=kq/d^2
E= V/d
E=kq/q
The Attempt at a Solution
There are many different formulas for electric field intensity.
In the first formula, it is inversely proportional to the square of the distances
That would give 4.8* 10^2 divided by 4.
The answer says E is independent of d. Where did they get that?
When the plates are connected , the electric field will be zero because it is connected to one another and would act as a conductor?