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sodaboy7
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Homework Statement
Two capacitors C1=4μf, C2= 12μf are connected in parallel across 12V battery. Then they are collected in parallel, with positive side of one capacitor to the negative side of the other. Find the resulting potential difference.
Answer (as on back-pages): 3.50V
Homework Equations
Cparallel= C1 + C2
1/Cseries= 1/C1 + 1/C2
The Attempt at a Solution
Firstly they are connected parallel and equivalent capacitance is 16μf and total charge is 192μC (144 + 48). Then they are connected in a combination which is as good as series hence now charges on each capacitor will be same also net capacitance is 3μf.
3*10^(-6)*V= 192*10^(-6) = 64V (not working!)