- #1

- 10

- 0

So,

f= 16 cm

do = 20 cm

m=-di/do, since the object and image have the same size and orientation,

m=1, so -di=do > -di=20cm > di= -20cm

And that's about where I left it. Does anyone have any input they can contribute?

Much appreciated...

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- Thread starter Jared944
- Start date

- #1

- 10

- 0

So,

f= 16 cm

do = 20 cm

m=-di/do, since the object and image have the same size and orientation,

m=1, so -di=do > -di=20cm > di= -20cm

And that's about where I left it. Does anyone have any input they can contribute?

Much appreciated...

- #2

- 13

- 0

Treat the real image of the first lens as the virtual object(o = negative) for the second lens. Treat the virtual image of the first lens as the real object(o = positive) for the second lens. Using the equation 1/o + 1/i = 1/f, and there you go.

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