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A coin is located 20.0 cm to the left of a converging lens (f=16.0 cm). A second identical lens is placed to the right of the first lens, such that the image formed by the combination has the same size and orientation as the original coin. Find the separation between the lenses.
So,
f= 16 cm
do = 20 cm
m=-di/do, since the object and image have the same size and orientation,
m=1, so -di=do > -di=20cm > di= -20cm
And that's about where I left it. Does anyone have any input they can contribute?
Much appreciated...
So,
f= 16 cm
do = 20 cm
m=-di/do, since the object and image have the same size and orientation,
m=1, so -di=do > -di=20cm > di= -20cm
And that's about where I left it. Does anyone have any input they can contribute?
Much appreciated...