Two dimensional kinematics (component velocity)

AI Thread Summary
The given velocity vector v=4.13i+6.76j m/s indicates that the velocity in the x-direction is 4.13 m/s and in the y-direction is 6.76 m/s. While these values represent the instantaneous components of velocity, they do not imply that the horizontal and vertical components are constant throughout the motion. Changes in velocity can occur due to acceleration or other forces acting on the object. Therefore, it is essential to analyze the specific conditions of the problem to determine if the components remain constant. Understanding these principles is crucial for solving two-dimensional kinematics problems effectively.
indietro
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Homework Statement


When a problem tells me that the velocity at some h is v=4.13i+6.76j m/s
does that mean that the velocity in xdirection = 4.13 m/s and the velocity in the ydirection = 6.76 m/s. and so are the horizontal and vertical components of velocity constant?


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indietro said:

Homework Statement


When a problem tells me that the velocity at some h is v=4.13i+6.76j m/s
does that mean that the velocity in xdirection = 4.13 m/s and the velocity in the ydirection = 6.76 m/s.
Yes.

... and so are the horizontal and vertical components of velocity constant?
Not necessarily.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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